在SQL SERVER中使用Long和Lat计算点之间的距离

时间:2017-08-03 11:46:08

标签: sql sql-server tsql latitude-longitude

我正在使用以下目的地

[BMAnalytics].[dbo].[EUACTIVESTORES]

它有列

[Store No]
[Lat]
[Long]

我可以使用这些列自行加入[Store No],因此我将Store to Store的每个组合列在两列中,称为“Source”& '目标'

然后在第三列中可以计算两者之间的距离吗?

我之前使用过以下内容,但这仅适用于单点指向,

DECLARE @source geography = 'POINT(0 51.5)'
DECLARE @target geography = 'POINT(-3 56)'

SELECT (@source.STDistance(@target))/1000

理想情况下,我希望从每个分支到每个分支的距离等。

欢迎任何指导

2 个答案:

答案 0 :(得分:3)

以下是使用自我加入的快速示例

如果可以,我建议在源表中添加一个包含地理点的字段,这样就无需在每次运行查询时计算此值。

示例

Declare @YourTable table ([Store No] int,Lat float,Lng float)
Insert Into @YourTable values
 (1,-8.157908, -34.931675)
,(2,-8.164891, -34.919033)  
,(3,-8.159999, -34.939999)  

Select [From Store] = A.[Store No]
      ,[To Store]   = B.[Store No]
      ,Meters       = GEOGRAPHY::Point(A.[Lat], A.[Lng], 4326).STDistance(GEOGRAPHY::Point(B.[Lat], B.[Lng], 4326))
 From  @YourTable A
 Join @YourTable B on A.[Store No]<>B.[Store No]

<强>返回

enter image description here

  

编辑如果您可以添加地理字段

Update YourTable Set GeoPoint = GEOGRAPHY::Point([Lat], [Lng], 4326)

然后计算

,Meters = A.GeoPoint.STDistance(B.GeoPoint)

答案 1 :(得分:3)

最终查询类似:

SELECT
      A.[STORE NO] AS 'SOURCE'
      ,B.[STORE NO] AS 'TARGET'
      ,CONVERT(DECIMAL(6,2),(((GEOGRAPHY::Point(A.[Lat], A.[Long], 4326).STDistance(GEOGRAPHY::Point(B.[Lat], B.[Long], 4326)))/1000)/8)*5) AS 'MILES'

FROM
      [bhxsql2014-dev].[BMAnalytics].[dbo].[EUACTIVESTORES] A
JOIN
      [bhxsql2014-dev].[BMAnalytics].[dbo].[EUACTIVESTORES] B on A.[Store No]<>B.[Store No]

WHERE 
         A.LAT        IS NOT NULL
     AND A.[STORE NO] IS NOT NULL
     AND B.LAT        IS NOT NULL
     AND B.[STORE NO] IS NOT NULL