Question

我有一个名为duration_d的列varchar2，该表中的数据如下所示

duration_d
-----------
12:25
01:35
12:10
04:21
12:18
12:24

我在下面尝试了查询

SELECT SUM( to_date( duration_d, 'mi:ss' ))
  FROM table 
 GROUP BY calling_number;

当我执行它后出现错误

ORA-00933: SQL command not properly ended
00933. 00000 -  "SQL command not properly ended"

任何人都可以告诉我如何计算它吗？

Answer 1

要获得一天的分数，您可以使用：

SELECT SUM( TO_DATE( duration_d, 'MI:SS' ) - TO_DATE( '00:00', 'MI:SS' ) ) AS total
FROM   your_table

结果如下：

TOTAL
------------------------------------------
0.0383449074074074074074074074074074074074

要将此转换为区间数据类型，您可以使用NUMTODSINTERVAL：

SELECT NUMTODSINTERVAL(
         SUM( TO_DATE( duration_d, 'MI:SS' ) - TO_DATE( '00:00', 'MI:SS' ) ),
         'DAY'
       ) AS total
FROM   your_table

结果如下：

TOTAL
-------------------
+00 00:55:13.000000

Answer 2

请尝试以下：

with x as 
(select sum((regexp_substr(YOUR_COLUMN, '[0-9]+', 1, 1)*60) + 
             regexp_substr(id, '[0-9]+', 1, 2)) seconds 
from YOUR_TABLE)
SELECT 
    TO_CHAR(TRUNC(seconds/3600),'FM9900') || ':' ||
    TO_CHAR(TRUNC(MOD(seconds,3600)/60),'FM00') || ':' ||
    TO_CHAR(MOD(seconds,60),'FM00')
FROM x

仅在持续时间始终为[MI：SS]时才会起作用。

您也可以根据自己的要求添加群组。

将秒数转换为所需的持续时间格式Reference。

分组

with x as 
(select calling_number,sum((regexp_substr(YOUR_COLUMN, '[0-9]+', 1, 1)*60) + 
             regexp_substr(id, '[0-9]+', 1, 2)) seconds 
from YOUR_TABLE
group by calling_number)
SELECT calling_number, 
    TO_CHAR(TRUNC(seconds/3600),'FM9900') || ':' ||
    TO_CHAR(TRUNC(MOD(seconds,3600)/60),'FM00') || ':' ||
    TO_CHAR(MOD(seconds,60),'FM00')
FROM x

Answer 3

使用SUBSTR，to_char，to_date，NVL，INSTR，reverse和SUM的组合。< / p>

SELECT "calling_number",
to_char(to_date(SUM(NVL(SUBSTR("duration_d", 0, INSTR("duration_d", ':')-1), "duration_d"))*60 +
SUM(substr("duration_d", - instr(reverse("duration_d"), ':') + 1)),'sssss'),'hh24:mi:ss') AS SUM_DURATION_D
FROM yourtable
GROUP BY "calling_number"

输出

calling_number  SUM_DURATION_D
1               00:26:10
2               00:29:03

SQL小提琴：http://sqlfiddle.com/#!4/9b0a81/33/0

Answer 4

正确拼写如下

SELECT SUM( TO_DATE( duration_d, 'mi:ss' ) )
 FROM YOURTABLE Group By calling_number

在oracle中如何总结分钟和秒？

4 个答案: