我无法理解数据的最终位置。
我已经编写了一个测试,以确保我的Publisher
类成功发送数据,并且如果我绑定了该数据,则会收到此数据。
该类本身继承自Thread
,并公开了publish()
方法,我可以调用该方法将数据传递给订阅者,通过Queue()
广播。
然而,在我的测试中,数据永远不会到来。我确保使用相同的 端口,我无法想到这里还有什么问题。
我是ZeroMQ新手,但我之前设法让PubSub
模式工作。
测试代码:
# Import Built-ins
import time
import json
import queue
from queue import Queue
from threading import Thread
# Import Third-Party
import zmq
def test_publisher_sends_data(self):
port = 667
name, topic, data = 'TestNode', 'testing', ['this', 'is', 'data']
encoded_name = json.dumps(name).encode('utf-8')
encoded_topic = json.dumps(topic).encode('utf-8')
encoded_data = json.dumps(data).encode('utf-8')
expected_result = (encoded_name, encoded_topic, encoded_data)
publisher = Publisher(port)
print("starting publisher")
publisher.start()
q = Queue()
def recv(q):
ctx = zmq.Context()
zmq_sock = ctx.socket(zmq.SUB)
print("Connecting to publisher")
zmq_sock.connect('tcp://127.0.0.1:%s' % port)
while True:
print("waiting for data..")
q.put(zmq_sock.recv_multipart())
print("data received!")
t = Thread(target=recv, args=(q,))
t.start()
print("sending data via publisher")
for i in range(5):
self.assertTrue(publisher.publish(name, topic, data))
time.sleep(0.1)
print("checking q for received data..")
try:
result = q.get(block=False)
except queue.Empty:
self.fail("Queue was empty, no data received!")
self.assertEqual(expected_result, result)
Publisher
班级
# Import Built-Ins
import logging
import json
from queue import Queue
from threading import Thread, Event
# Import Third-Party
import zmq
class Publisher(Thread):
"""Publisher Class which allows publishing data to subscribers.
The publishing is realized with ZMQ Publisher sockets, and supports publishing
to multiple subscribers.
The run() method continuosly checks for data on the internal q, which is fed
by the publish() method.
"""
def __init__(self, port, *args, **kwargs):
"""Initialize Instance.
:param port:
"""
self.port = port
self._running = Event()
self.sock = None
self.q = Queue()
super(Publisher, self).__init__(*args, **kwargs)
def publish(self, node_name, topic, data):
"""Publish the given data to all current subscribers.
All parameters must be json-serializable objects
:param data:
:return:
"""
message_parts = [json.dumps(param).encode('utf-8')
for param in (node_name, topic, data)]
if self.sock:
self.q.put(message_parts)
return True
else:
return False
def join(self, timeout=None):
self._running.clear()
try:
self.sock.close()
except Exception:
pass
super(Publisher, self).join(timeout)
def run(self):
self._running.set()
ctx = zmq.Context()
self.sock = ctx.socket(zmq.PUB)
self.sock.bind("tcp://*:%s" % self.port)
while self._running.is_set():
if not self.q.empty():
msg_parts = self.q.get(block=False)
print("Sending data:", msg_parts)
self.sock.send_multipart(msg_parts)
else:
continue
ctx.destroy()
self.sock = None
答案 0 :(得分:2)
添加.setsockopt( zmq.SUBSCRIBE, someNonZeroLengthSTRING )
如
SUB
- 套接字实例没有订阅(自然)
如果任何传入的消息无法匹配任何字符串,SUB
- 订阅,本地.recv()
自然不会收到这样的。
鉴于您的代码没有明确订阅,没有这样的消息,可以满足主题过滤处理条件,Q.E.D。
另一个问题 - A" Late-joiner"麻烦 - 接下来可能会发生,如果单元测试设计是闪电般快速的,那么我可能为你的进一步(不仅是ZeroMQ)分布式系统设计推荐的最好的下一步是花费时间与神话般的Pieter HINTJENS'预订" Code Connected,第1卷" 。任何认真对待异构分布式系统信令/消息传递的人都会喜欢他分享技术和非技术观点和意见。