Question

不是SQL的专家，但我设法让这个查询工作并提供我需要的结果。诀窍是让它表现出色。这两个表格中都有大约6密耳的记录。它目前运行大约3分钟，这是我需要它的方式。

SELECT p.id,
       match.weight
FROM store_promotions p
LEFT JOIN
  ( SELECT *
   FROM
     (SELECT id,
             (facets.weight::int * 1.5) AS weight
      FROM store_promotions promos
      JOIN -- this will return all promos, but add weight of 1.5 to the ones that are better matched to customer

        (SELECT (jsonb_array_elements(product) ->> 'key') AS barcode,
                (jsonb_array_elements(product) ->> 'doc_count') AS weight
         FROM customer_transaction_facets
         WHERE account_id = '1234567890') facets ON promos.products @> to_jsonb(facets.barcode::text)
      UNION SELECT id,
                   (facets.weight::int * .75) AS weight -- this will return all promos, but add weight of .75 for department matches to the ones that are better matched to customer
      FROM store_promotions promos
      JOIN
        (SELECT (jsonb_array_elements(department) ->> 'key') AS department,
                (jsonb_array_elements(department) ->> 'doc_count') AS weight
         FROM customer_transaction_facets
         WHERE account_id = '1234567890') facets ON promos.departments @> to_jsonb(facets.department::text)) matches) AS MATCH ON p.id = match.id WHERE storeid = '637'

Answer 1

select id, weight
from 
    store_promotions promos
    left join (
        select 
            (jsonb_array_elements(product) ->> 'key') as key,
            (jsonb_array_elements(product) ->> 'doc_count')::int * 1.5 as weight
        from customer_transaction_facets
        where account_id = '1234567890'
        union
        select 
            (jsonb_array_elements(department) ->> 'key') as key,
            (jsonb_array_elements(department) ->> 'doc_count')::int * 0.75 as weight
        from customer_transaction_facets
        where account_id = '1234567890'
    ) facets on 
        promos.products @> to_jsonb(facets.key::text)
        or
        promos.departments @> to_jsonb(facets.key::text)
where storeid = '637'

Postgres Multiple Joins

1 个答案: