Question

我正在尝试在未来x天生成一系列48个周期，并在可用的源表（T1）中显示匹配数据，但这似乎就像内部联接一样，只显示具有匹配T1的结果？

select
seq.date,
t1.date,
hh.period,
t1.period
From

myTable t1
right outer  join  (select date(date) from generate_series(current_date,current_date + '12 days'::interval ,'1 day'::interval) date)as  seq 
 ON (seq.date= t1.date)
right outer join (select period from generate_series (1,48) period) hh 
ON (hh.period = t1.period)

Answer 1

交叉加入该系列，然后离开加入表格

手机...

select seq.date, t1.date, hh.period, t1.period From (select date(date) 
from generate_series(current_date,current_date + '12 days'::interval ,'1 day'::interval) date)as seq 
cross join (select period from generate_series (1,48) period) hh
Left join my table
 ON (hh.period = t1.period)
And (seq.date= t1.date)

Postgres SQL多个外连接生成时间序列

1 个答案: