Question

我只是想验证一个tic tac toe board，其值在列表列表中。

board = ([1, 2, 0], [2, 1, 0], [2, 1, 2])


def print_winner(variable):
    if variable == 1:
        return print("Winner of this board is Player1")
    else:
        return print("Winner of this board is Player2")


def interpret(game_board):
    if game_board[0][0] != 0:
        if game_board[0][1] and game_board[0][2] == game_board[0][0]:
            print(print_winner(game_board[0][0]))
        elif game_board[1][0] and game_board[2][0] == game_board[0][0]:
            print(print_winner(game_board[0][0]))
        elif game_board[1][1] and game_board[2][2] == game_board[0][0]:
            print(print_winner(game_board[0][0]))
    elif game_board[0][1] != 0:
        if game_board[1][1] and game_board[2][1] == game_board[0][1]:
            print(print_winner(game_board[0][0]))
    elif game_board[0][2] != 0:
        if game_board[1][2] and game_board[2][2] == game_board[0][2]:
            print(print_winner(game_board[0][0]))
        elif game_board[1][2] and game_board[2][0]:
            print(print_winner(game_board[0][0]))
    elif game_board[1][0] != 0:
        if game_board[1][1] and game_board[1][2] == game_board[1][0]:
            print(print_winner(game_board[0][0]))
    elif game_board[2][0] != 0:
        if game_board[2][1] and game_board[2][2] == game_board[2][0]:
            print(print_winner(game_board[0][0]))
    else:
        print("No Winner")


interpret(board)

上面代码的问题是我不知道如何在我的第一个嵌套if语句失败后指示我的程序继续使用剩下的代码。因为我的代码没有给出任何输出。预期输出为"No winner"。

Answer 1

第一个问题是您错误地使用了and。您需要在and的任一操作数上指定条件。例如：

if game_board[0][1] == game_board[0][0] and game_board[0][2] == game_board[0][0]

OR

if game_board[0][1] == game_board[0][2] == game_board[0][0]

而不是：

if game_board[0][1] and game_board[0][2] == game_board[0][0]

但是，您也可以使用set并检查它是否只包含一个数字：

if len({game_board[0][0], game_board[0][1], game_board[0][2]}) == 1:

关于

的实际问题

一旦我的第一个嵌套if语句失败，如何指示我的程序继续使用剩下的代码

实际上非常简单。如果一个条件匹配，请使用普通if和return。

与其他一些改进（你总是打印game_board[0][0]）一起，它看起来像这样：

def interpret(game_board):
    if game_board[0][0] != 0:
        if len({game_board[0][0], game_board[0][1], game_board[0][2]}) == 1:
            return print(print_winner(game_board[0][0]))
        elif len({game_board[0][0], game_board[1][0], game_board[2][0]}) == 1:
            return print(print_winner(game_board[0][0]))
        elif len({game_board[0][0], game_board[1][1], game_board[2][2]}) == 1:
            return print(print_winner(game_board[0][0]))
    if game_board[0][1] != 0:
        if len({game_board[0][1], game_board[1][1], game_board[2][1]}) == 1:
            return print(print_winner(game_board[0][1]))
    if game_board[0][2] != 0:
        if len({game_board[0][2], game_board[1][2], game_board[2][2]}) == 1:
            return print(print_winner(game_board[0][2]))
        elif len({game_board[0][2], game_board[1][1], game_board[2][0]}) == 1:
            return print(print_winner(game_board[0][2]))
    if game_board[1][0] != 0:
        if len({game_board[1][0], game_board[1][1], game_board[1][2]}) == 1:
            return print(print_winner(game_board[1][0]))
    if game_board[2][0] != 0:
        if len({game_board[2][0], game_board[2][1], game_board[2][2]}) == 1:
            return print(print_winner(game_board[2][0]))
    return print("No Winner")

这是有效的，因为print会返回None并打印到stdout。

即使在嵌套if条件失败后如何继续执行部分执行

1 个答案: