使用来自缩写词的oddsratio()计算R中的比值比时出错

时间:2017-08-01 15:31:36

标签: r

我正在尝试计算焦虑率风险因素暴露水平的比值比,对于以下数据产生的数据:

data<-structure(list(exposure = structure(c(3L, 1L, 2L), .Label = c("mild", 
"severe", "unaffected"), class = "factor"), count_not_anxious = c(108, 
337, 203), count_anxious = c(8, 48, 76)), .Names = c("exposure", 
"count_not_anxious", "count_anxious"), row.names = c(NA, -3L), class = "data.frame") 

看起来像:

    exposure count_not_anxious count_anxious
1 unaffected               108             8
2       mild               337            48
3     severe               203            76

我专门为'epitools'包中的oddsratio()函数安排了数据,但oddsratio(data)生成以下错误消息:

Error in nrow(x) : object 'x' not found

这是为什么?我是否误解了如何为此功能安排数据?

提前感谢任何建议!

1 个答案:

答案 0 :(得分:1)

看起来你可以通过将数据从三列数据帧转换为两行矩阵来实现这一目标......

> dd <- as.matrix(data[,-1])  ## drop first column
> rownames(dd) <- data[,1]
> oddsratio(dd)

结果:

$data
           count_not_anxious count_anxious Total
unaffected               108             8   116
mild                     337            48   385
severe                   203            76   279
Total                    648           132   780

$measure
                        NA
odds ratio with 95% C.I. estimate    lower    upper
              unaffected 1.000000       NA       NA
              mild       1.891296 0.911011  4.46757
              severe     4.956366 2.432386 11.56705

$p.value
            NA
two-sided      midp.exact fisher.exact   chi.square
  unaffected           NA           NA           NA
  mild       9.001770e-02 1.289249e-01 9.505682e-02
  severe     1.579224e-06 1.755645e-06 6.787096e-06

$correction
[1] FALSE

attr(,"method")
[1] "median-unbiased estimate & mid-p exact CI"