我有一个像这样的数据框。
$a = [
'first' => '1st',
'second' => '2nd',
'third' => '3rd'
];
pull_by_key( $a, 'second' );
function pull_by_key( &$array, $key ){
$retval = $array[$key];
unset( $array[$key] );
return $retval;
}
echo "<pre>"; print_r($a); die;
我想从Project 4列中删除NaN值
我想要的输出应该是,
df,则
Project 4 Project1 Project2 Project3
0 NaN laptio AB NaN
1 NaN windows ten NaN
0 one NaN NaN
1 two NaN NaN
答案 0 :(得分:2)
如果数据框的索引只是标准的0到n个有序整数,则可以将Project4
列弹出一个系列,删除NaN
值,重置索引,然后将其合并为数据框。
import pandas a pd
df = pd.DataFrame([[pd.np.nan, 1,2,3],
[pd.np.nan, 4,5,6],
['one',7,8,9],
['two',10,11,12]], columns=['p4','p1','p2','p3'])
s = df.pop('p4')
pd.concat([df, ps.dropna().reset_index(drop=True)], axis=1)
# returns:
p1 p2 p3 p4
0 1 2 3 one
1 4 5 6 two
2 7 8 9 NaN
3 10 11 12 NaN