当bbox_inches ='紧'时,修剪3D pdf图(savefig)中的空白区域。和pad_inches没有所需的效果

时间:2017-07-28 18:40:08

标签: python matplotlib trim bounding-box removing-whitespace

通过下面的代码,我制作了一个我希望用pdf保存的图。我使用savefig命令:

fig.savefig("Surface_I.pdf" )

pdf文件在leftup中包含大量空格:

new answer

fig.savefig("Surface_I.pdf", bbox_inches='tight')解决方案会删除一些xz信息,而不会从lefttop中删除太多空间:

enter image description here

fig.savefig("Surface_I.pdf", bbox_inches='tight', pad_inches=0.3)解决方案会增加一些空间,修复刚删除的信息:

enter image description here

lefttop中仍有太多空间。

如何从pdf中移除或修剪所有lefttop空格?

注意:所有这些图片都是pdf生成的屏幕截图。

代码:

import numpy as np
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt

# Function:
z_fit = a0 + a1*yy + a2*xx + a3*yy**2 + a4*xx**2  + a5*xx*yy

# Parameters:
a0 =  -941.487789948
a1 =  0.0146881652963
a2 =  -2.53533353374e-05
a3 =  -9.64343252786e-05
a4 =  -2.47416662598e-08
a5 =  3.77136886946e-07

x_mesh = np.linspace(10.0000000000000, 2000.0000000000000, 20)
y_mesh = np.linspace(-4.4119598462100, 10.8557347078000, 20)

xx, yy = np.meshgrid(x_mesh, y_mesh)


# Plot the function
fig = plt.figure()
ax = fig.gca(projection='3d')

ax.plot_surface(xx, yy, z_fit, color='b', alpha=0.5)

ax.set_xlabel('\nx')
ax.set_ylabel('y')
ax.set_zlabel('\nzzzzz zzz', linespacing=3)
ax.set_title('\n\nSurface I', linespacing=3)
xlabels=[0, 250, 500, 750, 1000, 1250, 1500, 1750, 2000]
ax.set_xticklabels(xlabels,rotation=90,
                  verticalalignment='baseline',#)#,
                  horizontalalignment='left')

ylabels = [-4, -2, 0, 2, 4, 6, 8, 10]
ax.set_yticklabels(ylabels,rotation=0,
                  verticalalignment='baseline')#,
#                 horizontalalignment='left')


fig.savefig("Surface_I.pdf", bbox_inches='tight', pad_inches=0.3)

2 个答案:

答案 0 :(得分:0)

尝试更改下面代码中的列表边框(border = [xmin,ymin,xmax,ymax]在数字设备坐标中) 创建一个大小边框列表的轴ax0有点棘手 并在里面添加3d图形的轴。 尝试使用border = [-0.5,0,1.5,1]你将理解这个列表的作用

import numpy as np
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt

# Parameters:
a0 =  -941.487789948
a1 =  0.0146881652963
a2 =  -2.53533353374e-05
a3 =  -9.64343252786e-05
a4 =  -2.47416662598e-08
a5 =  3.77136886946e-07

x_mesh = np.linspace(10.0000000000000, 2000.0000000000000, 20)
y_mesh = np.linspace(-4.4119598462100, 10.8557347078000, 20)

xx, yy = np.meshgrid(x_mesh, y_mesh)

# Function:
z_fit = a0 + a1*yy + a2*xx + a3*yy**2 + a4*xx**2  + a5*xx*yy


def axesborder(border):
    # border  = [xmin,ymin,xmax,ymax] 
    # return [xmin,ymin,dx,dy]
    return [border[0],border[1],border[2]-border[0],border[3]-border[1]]

# Plot the function
fig = plt.figure(1)
fig.set_size_inches((16,9), forward=True)
border = [-0.1,0,1.05,1]
#border = [0,0,1,1]
ax0 = fig.add_axes(axesborder(border))
ax0.set_axis_off()

ax = fig.add_axes(ax0.get_position(),projection='3d',zorder = 1)

ax.plot_surface(xx, yy, z_fit, color='b', alpha=0.5)

ax.set_xlabel('\nx')
ax.set_ylabel('y')
ax.set_zlabel('\nzzzzz zzz', linespacing=3)
ax.set_title('\n\nSurface I', linespacing=3)
xlabels=[0, 250, 500, 750, 1000, 1250, 1500, 1750, 2000]
ax.set_xticklabels(xlabels,rotation=90,
                  verticalalignment='baseline',#)#,
                  horizontalalignment='left')

ylabels = [-4, -2, 0, 2, 4, 6, 8, 10]
ax.set_yticklabels(ylabels,rotation=0,verticalalignment='baseline')

plt.show()

plt.savefig('test.pdf')

答案 1 :(得分:0)

我像这样手动裁剪生成的pdf图:

pdfcrop --margins '0 0 0 0' input.pdf output.pdf

来自pdfcrop帮助消息:

--margins "<left> <top> <right> <bottom>"

如果需要裁剪许多图,则可以编写一个简单的bash脚本来自动化该过程。整个解决方案有点难看,但是可以用。