Question

我正在关注Django By Example教程，无法关注用户。我点击了关注按钮但没有任何反应。我一遍又一遍地浏览了那个部分，复制并粘贴了代码。它仍然无法运作。

以下是我的观点

view

这是我的html块中的ajax

@ajax_required
@require_POST
@login_required
def user_follow(request):
    user_id = require.POST.get('id')
    action = request.POST.get('action')
    if user_id and action:
        try:
            user = User.objects.get(id=user_id)
            if action == 'follow':
                Contact.objects.get_or_create(user_form=request.user,user_to=user)
            else:
                Contact.objects.filter(user_form=request.user,user_to=user).delete()
            return JsonResponse({'status':'ok'})
        except User.DoesNotExist:
            return JsonResponse({'status':'ko'})
    return JsonResponse({'status':'ko'})

这是网址

**

 {% block domready %}
$('a.follow').click(function(e){
e.preventDefault();
$.post('{% url "user_follow" %}',
{
id: $(this).data('id'),
action: $(this).data('action')
},
function(data){
if (data['status'] == 'ok') {
var previous_action = $('a.follow').data('action');
// toggle data-action
$('a.follow').data('action',
previous_action == 'follow' ? 'unfollow' : 'follow');

// update total followers
var previous_followers = parseInt(
$('span.count .total').text());
$('span.count .total').text(previous_action == 'follow' ?
previous_followers + 1 : previous_followers - 1);
}
}
);
});
{% endblock %}

**

感谢您的帮助

Answer 1

视图应该是

@ajax_required
@require_POST
@login_required
def user_follow(request):
    user_id = request.POST.get('id')
    action = request.POST.get('action')
    if user_id and action:
        try:
            user = User.objects.get(id=user_id)
            if action == 'follow':
                Contact.objects.get_or_create(user_from=request.user,user_to=user)
            else:
                Contact.objects.filter(user_form=request.user,user_to=user).delete()
            return JsonResponse({'status':'ok'})
        except User.DoesNotExist:
            return JsonResponse({'status':'ko'})
    return JsonResponse({'status':'ko'})

Answer 2

你错误地将你的状态值'ok'拼错为'ko' 请将其更改为“确定”

    except User.DoesNotExist:
            return JsonResponse({'status':'ok'})
    return JsonResponse({'status':'ok'})

我希望在检查你的js代码时这是一个简单的错误。？

构建AJAX视图以关注用户

2 个答案: