Question

所以我有一个允许你关注用户的系统。所以这是follow.php

的代码

<?php
error_reporting(0);

session_start();

include_once 'db.php';

$username =  htmlspecialchars($_GET['fuser'], ENT_QUOTES, 'UTF-8');
$follower = $_SESSION['user'];
$type = 'Following';


if($username == $follower){
    header('Location: index.php');
}


if($_SESSION['loggedIn'] == true && $follower != $username){
    $result = $con->prepare("SELECT * FROM followers WHERE follow_to = :post_id");
    $result->bindParam(':post_id', $username);
    $result->execute();
    $reprint = $result->rowCount();
}

if($result->rowCount() < 1){
    //Notifcation handler 
    $notf = $con->prepare("INSERT INTO notifications (from_user, to_user, type) VALUES (:cuser, :tuser, :type)");
    $notf->bindValue(':cuser', $_SESSION['user'], PDO::PARAM_STR);
    $notf->bindValue(':tuser', $username, PDO::PARAM_STR);
    $notf->bindValue(':type', $type, PDO::PARAM_STR);
    $notf->execute();

    //Insert into followers
    $stmt = $con->prepare("INSERT INTO followers (follow_from, follow_to) VALUES (:ff, :ft)");
    $stmt->bindValue(':ff', $follower, PDO::PARAM_STR);
    $stmt->bindValue(':ft', $username, PDO::PARAM_STR);
    $stmt->execute();

}
//Display follower
$stmt1 = $con->prepare("SELECT COUNT(*) AS count FROM followers WHERE follow_to = :username");
$stmt1->bindValue(':username', $username, PDO::PARAM_STR);
$stmt1->execute();
$likes = $stmt1->fetchAll(PDO::FETCH_ASSOC);

$qry = $con->prepare("SELECT follow_from, follow_to FROM followers");
$qry->execute();
$followers = $qry->fetchAll(PDO::FETCH_ASSOC);
header('Location: ' . $_SERVER['HTTP_REFERER']);
exit();

?>

当我尝试跟踪用户所发生的一切时，我会重定向到$_SERVER['HTTP_REFERER']。这让我觉得最后的if语句没有被处理。所以这是表格布局

+-------------+------------------+------+-----+---------+----------------+
| Field       | Type             | Null | Key | Default | Extra          |
+-------------+------------------+------+-----+---------+----------------+
| id          | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| follow_from | varchar(255)     | YES  |     | NULL    |                |
| follow_to   | varchar(255)     | YES  |     | NULL    |                |
+-------------+------------------+------+-----+---------+----------------+

我认为这可能是我查询的问题。有任何想法吗？

Answer 1

我建议进行以下更改。在您的原始帖子中，您正在查看关注者表中的任何记录，其中follow_to是您希望关注的人。这意味着如果其他人关注此用户，则根据您的逻辑，将不会发生新的以下操作。

我修改了您的初始sql，以检查已登录用户已按照请求的用户进行匹配的记录。

我添加了一个初始化为0的$ reprint变量。如果没有用户登录，则不会发生任何事情。如果用户已登录，但关注者表中不存在任何记录，则会将新条目插入关注者和通知中。

否则，它不会插入并执行脚本的其余部分。

<?php
error_reporting(0);

session_start();

include_once 'db.php';

$username =  htmlspecialchars($_GET['fuser'], ENT_QUOTES, 'UTF-8');
$follower = $_SESSION['user'];
$type = 'Following';


if($username == $follower){
    header('Location: index.php');
}

$reprint = 0;

if($_SESSION['loggedIn'] == true && $follower != $username){
    $result = $con->prepare("SELECT * FROM followers WHERE follow_to = :post_id and follow_from = :from");
    $result->bindParam(':post_id', $username);
    $result->bindParam(':from', $follower);
    $result->execute();
    $reprint = $result->rowCount();
}

if($reprint < 1){
    //Notifcation handler 
    $notf = $con->prepare("INSERT INTO notifications (from_user, to_user, type) VALUES (:cuser, :tuser, :type)");
    $notf->bindValue(':cuser', $_SESSION['user'], PDO::PARAM_STR);
    $notf->bindValue(':tuser', $username, PDO::PARAM_STR);
    $notf->bindValue(':type', $type, PDO::PARAM_STR);
    $notf->execute();

    //Insert into followers
    $stmt = $con->prepare("INSERT INTO followers (follow_from, follow_to) VALUES (:ff, :ft)");
    $stmt->bindValue(':ff', $follower, PDO::PARAM_STR);
    $stmt->bindValue(':ft', $username, PDO::PARAM_STR);
    $stmt->execute();

}
//Display follower
$stmt1 = $con->prepare("SELECT COUNT(*) AS count FROM followers WHERE follow_to = :username");
$stmt1->bindValue(':username', $username, PDO::PARAM_STR);
$stmt1->execute();
$likes = $stmt1->fetchAll(PDO::FETCH_ASSOC);

$qry = $con->prepare("SELECT follow_from, follow_to FROM followers");
$qry->execute();
$followers = $qry->fetchAll(PDO::FETCH_ASSOC);
header('Location: ' . $_SERVER['HTTP_REFERER']);
exit();

?>

无法关注其他用户

1 个答案: