Question

列表的元素表示x和y十进制度坐标对，其中x和y坐标之间的空格格式为字符串：

'34.894127 29.761515', '32.323574 30.166336', '32.677296 31.961439', '35.298668 31.559237', '34.894127 29.761515

到目前为止，我可以选出第一个元素并将其设置为x值：

x = mystring[0:mystring.find(' ')]

如何迭代此字符串以生成一个由此字符串中的x和y坐标对组成的数组？

Answer 1

mystring = mystring = "'34.894127 29.761515', '32.323574 30.166336', '32.677296 31.961439', '35.298668 31.559237', '34.894127 29.761515"你可以得到一对像这样的对：

x = [pair.lstrip().strip("'").split(' ') for pair in mystring.split(',')]
# gives: [['34.894127', '29.761515'], ['32.323574', '30.166336'], ['32.677296', '31.961439'], ['35.298668', '31.559237'], ['34.894127', '29.761515']]

或者如果你真的想要元组：

x = tuple([tuple(pair.lstrip().strip("'").split(' ')) for pair in mystring.split(',')])
# gives: (('34.894127', '29.761515'), ('32.323574', '30.166336'), ('32.677296', '31.961439'), ('35.298668', '31.559237'), ('34.894127', '29.761515'))

Answer 2

使用带有字符串作为输入的np.matrix的快速方法：

如果data是一个字符串，则它被解释为带逗号或的矩阵分隔列的空格和分隔行的分号。

string = ['34.894127 29.761515', '32.323574 30.166336', '32.677296 31.961439', 
          '35.298668 31.559237', '34.894127 29.761515']

np.matrix(';'.join(string))
#matrix([[ 34.894127,  29.761515],
#        [ 32.323574,  30.166336],
#        [ 32.677296,  31.961439],
#        [ 35.298668,  31.559237],
#        [ 34.894127,  29.761515]])

string = "'34.894127 29.761515', '32.323574 30.166336', '32.677296 31.961439', '35.298668 31.559237', '34.894127 29.761515"

np.matrix(string.replace(',', ';'))
#matrix([[ 34.894127,  29.761515],
#        [ 32.323574,  30.166336],
#        [ 32.677296,  31.961439],
#        [ 35.298668,  31.559237],
#        [ 34.894127,  29.761515]])

Answer 3

您可以使用split(',')获取每个字符串，然后split()来获取坐标，例如使用list-comprehension：

mystring =  "'34.894127 29.761515', '32.323574 30.166336', '32.677296 31.961439', '35.298668 31.559237', '34.894127 29.761515'"
coordinates = [tuple(map(float, x.replace("'", '').split())) for x in mystring.split(',')]

输出：

[(34.894127, 29.761515), (32.323574, 30.166336), (32.677296, 31.961439), (35.298668, 31.559237), (34.894127, 29.761515)]

Answer 4

从字符串列表中获取numpy数组：

import numpy as np

string = ['34.894127 29.761515', '32.323574 30.166336', '32.677296 31.961439', 
          '35.298668 31.559237', '34.894127 29.761515']

s  = np.array(list(map(lambda x: x.split(" "), string))).astype(float)

这导致s

[[ 34.894127  29.761515]
 [ 32.323574  30.166336]
 [ 32.677296  31.961439]
 [ 35.298668  31.559237]
 [ 34.894127  29.761515]]

迭代字符串以创建Lat Long坐标数组

4 个答案: