Question

我正在使用查询：

select
  SGB_ID,
  max(SGB_TERM_CODE_EFF)max_term,
  SGB_TYP_CODE
from SGB
group by
  SGB_ID,
  SGB_TYP_CODE
order by 1

我得到多行，因为SGB_TYP_CODE具有不同的值。我只想要最大术语的结果。我尝试过使用'keep dense_rank'，但我无法让它工作。

感谢。

Answer 1

以下是使用MAX（）... KEEP（）：

的方法

with sgb ( sgb_id, sgb_term_code_eff, sgb_typ_code ) AS 
 ( SELECT 1, 'A', 'ACODE' FROM DUAL UNION ALL
   SELECT 1, 'B', 'BCODE' FROM DUAL UNION ALL
   SELECT 1, 'Z', 'ZCODE' FROM DUAL UNION ALL
   SELECT 1, 'D', 'DCODE' FROM DUAL UNION ALL
   SELECT 2, 'A', 'ACODE' FROM DUAL UNION ALL
   SELECT 2, 'Q', 'QCODE' FROM DUAL UNION ALL
   SELECT 2, 'Q', 'QCODE' FROM DUAL UNION ALL
   SELECT 3, 'A', 'ACODE' FROM DUAL )
SELECT sgb_id,
       MAX (sgb_term_code_eff) max_term,
       MAX (sgb_typ_code) KEEP ( DENSE_RANK FIRST ORDER BY sgb_term_code_eff DESC ) sgb_typ_code
FROM   sgb
GROUP BY sgb_id
ORDER BY 1

SGB_ID                                 MAX_TERM SGB_TYP_CODE 
-------------------------------------- -------- ------------ 
                                     1 Z        ZCODE
                                     2 Q        QCODE
                                     3 A        ACODE

完整示例：

<?php
session_start();
sleep(10);
echo "Loaded Page 1";
?>

Oracle SQL - 将结果限制为最大值

1 个答案: