Question

我一直在学习pyi中的gui。但我不知道如何将stringvar转换为int，以便我可以使用。我做了这个分数计算程序。

from tkinter import *

root = Tk()
root.geometry('300x300')
labelFrame = Frame(root)
labelFrame.pack(side='top')
topFrame = Frame(root)
bottomFrame = Frame(root)
topFrame.pack()
bottomFrame.pack(side='bottom')

l1 = Label(labelFrame, text='adi').pack(side='left')
l2 = Label(labelFrame, text='      appa  ').pack(side='left')
l3 = Label(labelFrame, text='      amma').pack(side='left')



class adi:
   def enter(self):
       self.entry = Entry(root, width=5)
       self.entry.pack(side='left')
       self.entry = StringVar(self.entry)
       self.entry = int(self.entry)

   def submit(self):
       self.middleFrame = Frame(root)
       self.middleFrame.pack()
       if self.entry < 250:
           self.eentry = StringVar(self.entry)
           self.label = Label(middleFrame, text=eentry, 
width=6).pack(side='left')
      else:
          self.label1 = Label(middleFrame, text='your out', 
width=6).pack(side='left')


adi = adi()

button = Button(topFrame, text=' enter  ', width=5, 
command=adi.enter()).pack(side='left')
button2 = Button(topFrame, text='enter 2', width=5, 
command=adi.enter()).pack(side='left')
button3 = Button(topFrame, text='enter 3', width=5, 
command=adi.enter()).pack(side='left')
button4 = Button(bottomFrame, text='submit', width=5, 
command=adi.submit()).pack(side='bottom')

root.mainloop()

但是当我跑这个时，

C:\Users\adithya\AppData\Local\Programs\Python\Python36-32\python.exe C:/Users/adithya/Desktop/python/Adithya.py
Traceback (most recent call last):
  File "C:/Users/adithya/Desktop/python/Adithya.py", line 37, in <module>
    button = Button(topFrame, text=' enter  ', width=5, command=adi.enter()).pack(side='left')
  File "C:/Users/adithya/Desktop/python/Adithya.py", line 23, in enter
    self.entry = int(self.entry)
TypeError: int() argument must be a string, a bytes-like object or a number, not 'StringVar'

Process finished with exit code 1

这发生了。请帮我介绍如何将stringvar转换为int

如何在python中将stringvar转换为整数？

0 个答案: