Question

如何将此列表转换为没有＆＃39; - ＆＃39;在它里面它们都是整数？

List1 = ['978-0262133838','978-0262201-629','978-0321758927']

所以列表将类似于

List1 = [9780262133838, 9780262201629, 9780321758927]

Answer 1

使用.replace('-', '')的简单列表理解：

List1 = ['978-0262133838','978-0262201-629','978-0321758927']
print([x.replace('-','') for x in  List1])
# => ['9780262133838', '9780262201629', '9780321758927']

请参阅Python 3 demo

Answer 2

实现这一目标的大多数Pythonic方法是使用map lambda函数（用＆＃39;＆＃39;替换＆＃39;＆＃39;然后将其转换为int）：

>>> my_list = ['978-0262133838','978-0262201-629','978-0321758927']
>>> map(lambda x: int(x.replace('-', '')), my_list)
[9780262133838, 9780262201629, 9780321758927]

Answer 3

也许这会有所帮助。如果您的清单是：

List1 = ['978-0262133838','978-0262201-629','978-0321758927']

您可以像这样使用for循环，并创建一个新列表来保留新数字：

List2=[] #it is very important to have this list outside the for loop
For number in List1: #This does exactly what it says, you get the first number in the list, then you get the second and so on...
    number=number.replace("-","") # I use "" to refer strings, that's just how i learned.
    List2.append[int(number)]

如果变量号只是List1，那么只需输入

即可

List1=List2

希望它有所帮助，祝你好运：D

如何在python 3中将字符串转换为整数

3 个答案: