Question

关于使用LIKE %和CONCAT进行搜索，我已经查了很多回复，但他们并不适合我。基本上我试图在数据库中找到像％Croyden和Surrey这样的字词下面的脚本工作正常，但是我想对包含Croyden和Surrey的单词使用％。我尝试了各种方法，但没有任何效果。

$locTown = "Croydon";
$locCounty = "Surrey";

$query = 'SELECT locTown, locCounty FROM location where locTown LIKE ? AND locCounty LIKE ? ';

if ($stmt = mysqli_prepare($link, $query)) {

    mysqli_stmt_bind_param($stmt, "ss", $locTown, $locCounty);  

    mysqli_stmt_execute($stmt);

    mysqli_stmt_bind_result($stmt, $locTown, $locCounty);

    /* fetch value */
    mysqli_stmt_fetch($stmt);

    while (mysqli_stmt_fetch($stmt)) {

    }

    echo "Location: $locTown - $locCounty\n";

    /* close statement */
    mysqli_stmt_close($stmt);
}

mysqli_close($link);

只是为了Clarity，在更新SQL和Fething结果后，现在可以正常工作。

$query = "SELECT locTown, locCounty FROM location where locTown LIKE CONCAT('%', ?, '%') AND locCounty LIKE CONCAT('%', ?, '%') ";    

if ($stmt = mysqli_prepare($link, $query)) {

    mysqli_stmt_bind_param($stmt, "ss", $locTown, $locCounty);  

    mysqli_stmt_execute($stmt);

    mysqli_stmt_bind_result($stmt, $locTown, $locCounty);

    /* fetch value */
    mysqli_stmt_fetch($stmt);


    while (mysqli_stmt_fetch($stmt)) {

      echo "Location: $locTown - $locCounty\n";

    }


    /* close statement */
    mysqli_stmt_close($stmt);
}

mysqli_close($link);

Answer 1

由于查询中的%连接不适用于OP，因此您可以尝试在绑定时连接%：

mysqli_stmt_bind_param($stmt, "ss", '%'.$locTown, '%'.$locCounty);

PHP MySQL搜索db hat包含使用％Wildcard

1 个答案: