在许多表格php中搜索通配符

时间:2016-03-17 06:50:12

标签: php mysql

请帮助我,我想进行搜索查询但是表格的列表没有在php中显示但它在mysql中工作..这是我的代码

var inputs = $("[id^=txt]");

function UpdateGrid() {
  alert("complete")
}

$("#filterMeasurement").find("input[type=text]").change(function () {
    var res = $.grep(inputs, function(el) {
      return el.value.length > 0 && !/^\s+$/.test(el.value)
    });
  
    if (res.length === inputs.length) {
      UpdateGrid();
    }
    else {
      // get alert only on last textbox on change 
      // by checking all textboxes as mandatory
      // if any input elements do not have value 
      // then alert("Fill all the fields") 
      //if (res.length === inputs.length - 1) {
         alert("Fill all the fields")
      //}
    }
});

继续这里

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js">
</script>
<div id="filterMeasurement" class="col-md-4 col-sm-6 col-xs-12 filterControls">
    <h4>Measurements in (mm)</h4>
    <div class="mea-bx">
        <h5>Length </h5>
        <div>
            <input name="txtLengthFrom" type="text" id="txtLengthFrom" class="textSmLeft" placeholder="from" />
            <input name="txtLengthTo" type="text" id="txtLengthTo" class="textSmRight" placeholder="to" />
        </div>
    </div>
    <div class="mea-bx">
        <h5>Width </h5>
        <div>
            <input name="txtWidthFrom" type="text" id="txtWidthFrom" class="textSmLeft" placeholder="from" />
            <input name="txtWidthTo" type="text" id="txtWidthTo" class="textSmRight" placeholder="to" />
        </div>
    </div>
    <div class="mea-bx">
        <h5>Height </h5>
        <div>
            <input name="txtHeightFrom" type="text" id="txtHeightFrom" class="textSmLeft" placeholder="from" />
            <input name="txtHeightTo" type="text" id="txtHeightTo" class="textSmRight" placeholder="to" />
        </div>
    </div>
</div>

1 个答案:

答案 0 :(得分:1)

您只能从if(isset($data["cia"])){ $cia .= $data["cia"] . "\r\n"; } 中选择table_name,然后再执行information_schema.tables。选择结果中没有WHERE code=...,所以这不起作用。

如果我正确地完成了你要做的事情,你必须分两步完成:

Code