如何从Google商家信息中获取一系列地点的坐标,然后在完成所有操作后使用结果?

时间:2017-07-24 21:59:20

标签: javascript node.js promise google-places-api google-places

我有一系列地名,例如:

const places = ['King Square, London', 'Empire State Building', 'Great Wall of China'];

我需要一个新的对象数组,并为地名数组中的每个元素设置位置,例如:

const places = [
  { name: 'King Square, London', position: { latitude: ..., longitude: ... } },
  ...
];

我认为我必须做这样的事情:

const places = [];

['King Square, London', 'Empire State Building', 'Great Wall of China'].forEach(placeName => {
  axios
  .get(`https://maps.googleapis.com/maps/api/place/textsearch/json?key=GOOGLE_PLACES_API_KEY&query=${placeName}`)
  .then(response => {
    if (!!response && !!response.results && !!response.results[0]) {
      const searchResult = response.results[0];

      if (!!searchResult) {
        axios
          .get(`https://maps.googleapis.com/maps/api/place/details/json?key=GOOGLE_PLACES_API_KEY&placeid=${searchResult.place_id}`)
          .then(response => {
            const placeResult = response.result;

            if (!!placeResult) {
              places.push({ name: placeName, position: placeResult.geometry.location })

但它似乎不起作用。

它应该是什么样的,我可以填充places并在填充后使用该数组?我是否必须使用Promise来确保它在使用之前已填充?

1 个答案:

答案 0 :(得分:2)

使用Promise.all()

更新现有代码的步骤:

  1. 使用Array.map()代替forEach()将数据存储在数组中。
  2. 让回复map() 返回承诺(即axios.get().then()的返回值)。
  3. axios.get()的调用的响应将包含包含结果的数据属性,因此请使用response.data.results代替response.results
  4. 再次回复承诺
  5. 然后在设置promises数组之后,可以使用Promise.all():

    const places = [];
    //1 - store promises in an array
    var promises = ['King Square, London', 'Empire State Building', 'Great Wall of China'].map(placeName => {
      return axios //2 - return promise
      .get(`https://maps.googleapis.com/maps/api/place/textsearch/json?key=GOOGLE_PLACES_API_KEY&query=${placeName}`)
      .then(response => {
        //3 - use response.data.results instead of response.results
        if (!!response && !!response.data && !!response.data.results && !!response.data.results[0]) {
          const searchResult = response.data.results[0];
    
          if (!!searchResult) {
            return axios //4 return nested promise
              .get(`https://maps.googleapis.com/maps/api/place/details/json?key=GOOGLE_PLACES_API_KEY&placeid=${searchResult.place_id}`)
              .then(response => {
                const placeResult = response.data.result;
    
                if (!!placeResult) {
                  places.push({ name: placeName, position: placeResult.geometry.location });
                }
              })
          }
        }
      });
    });
    //5 - After promises are done, use the places array
    Promise.all(promises).then(results => {
        console.log('places:', places);
    })
    
  6. 输出

    places: [ { name: 'King Square, London',
        position: { lat: 51.52757920000001, lng: -0.0980441 } },
      { name: 'Great Wall of China',
        position: { lat: 40.4319077, lng: 116.5703749 } },
      { name: 'Empire State Building',
        position: { lat: 40.7484405, lng: -73.98566439999999 } } ]
    

    客户端Javascript中的示例

    以下是(客户端)JavaScript的端口。请注意它是如何非常相似但使用StackOverflow API(因为这样就不会有CORS问题)。

    var ranks = [];
    var promises = [94, 95].map(badgeId => {
      return axios.get(`https://api.stackexchange.com/2.2/badges/${badgeId}?site=stackoverflow&order=desc&sort=rank&filter=default`)
        .then(response => {
          var responsebadgeId = response.data.items[0].badge_id;
          return axios.get(`https://api.stackexchange.com/2.2/badges/${responsebadgeId}/recipients?site=stackoverflow`)
            .then(response => {
              console.log('pushing rank into array from data: ',response.data.items[0].rank);
              ranks.push(response.data.items[0].rank);
            });
        });
    });
    Promise.all(promises).then(responses => {
      console.log('promises all callback - ranks:',ranks);
    });
    <script src="https://cdnjs.cloudflare.com/ajax/libs/axios/0.16.2/axios.min.js"></script>