如何从Android中的google places api获得超过20个结果

Question

我在应用程序中实现了google places api。但它只返回了20个结果。 检查发布的其他答案，从那里我开始知道我们需要为那个实现分页。 请提供一些解决方案。

我在这里附上代码

public ArrayList<Place> findPlaces(double latitude, double longitude,
        String placeSpacification) {

    ArrayList<Place> arrayList;
    String urlString = makeUrl(latitude, longitude, placeSpacification);
    System.out.println("url------"+urlString);

    try {
        String json = getJSON(urlString);

        System.out.println(json);
        JSONObject object = new JSONObject(json);

        JSONArray array = object.getJSONArray("results");
        arrayList = new ArrayList<Place>();
        for (int i = 0; i < array.length(); i++) {
            try {
                Place place = Place
                        .jsonToPontoReferencia((JSONObject) array.get(i));
                Log.v("Places Services ", "" + place);
                arrayList.add(place);
            } catch (Exception e) {
            }
        }

        return arrayList;
    } catch (JSONException ex) {

    }
    return null;
}

    private String makeUrl(double latitude, double longitude, String place) {
    StringBuilder urlString = new StringBuilder(
            "https://maps.googleapis.com/maps/api/place/search/json?");

    if (place.equals("")) {
        urlString.append("&location=");
        urlString.append(Double.toString(latitude));
        urlString.append(",");
        urlString.append(Double.toString(longitude));
        //urlString.append("&radius=2000");
         urlString.append("&types="+place);
        urlString.append("&sensor=false&key=" + API_KEY);
    } else {
        //urlString.append("rankby=2000&location=");
        urlString.append("&location=");
        urlString.append(Double.toString(latitude));
        urlString.append(",");
        urlString.append(Double.toString(longitude));
        urlString.append("&radius=2000");
        urlString.append("&types=" + place);
        urlString.append("&sensor=false&key=" + API_KEY);
    }

    return urlString.toString();
}

谢谢，