经过大量工作,我做了这个(正确的)查询:
select count(distinct t1.code+t1.flname+t1.col1+t2.flname)
from #t4 t1 cross apply (select flname from #t4 sq where sq.col1=t1.col1)t2
经过大量的工作后,我没有使用交叉申请而无法生成平等查询。可能吗?也许与WITH?怎么样不使用WITH?
答案 0 :(得分:1)
简单的class Point {
private int x, y;
public Point(int x, int y) {
super(); // this is the change.
this.x = x;
this.y = y;
}
public Point() {
this(0, 0);
}
}
应该是等效的:
FormUrlEncodedContent