Question

Hibernate抛出这样的异常：

org.hibernate.QueryException: Expected positional parameter count: 2, actually detected 0
at org.hibernate.query.internal.QueryParameterBindingsImpl.verifyParametersBound(QueryParameterBindingsImpl.java:270)
at org.hibernate.query.internal.AbstractProducedQuery.beforeQuery(AbstractProducedQuery.java:1309)
at org.hibernate.query.internal.AbstractProducedQuery.list(AbstractProducedQuery.java:1408)
at org.hibernate.query.Query.getResultList(Query.java:146)
at pl.code.dao.PersonDAO.personExists(PersonDAO.java:59)

在这种方法中：

@Override
public boolean personExists(String firstName, String location) {
    TypedQuery<Person> query = entityManager.createQuery("Select p FROM Person p WHERE p.firstName = ? and p.location = ?", Person.class);
    List<Person> all = query.getResultList();
    return all.size() > 0 ? true : false;

}

我正在使用Hibernate版本5.2.9.Final。任何想法有什么不对？

Answer 1

请使用以下示例来传递您的参数

<cfmail to="myemail"
from="myemail"
subject="myemail"
type="text">
Dear myemail

We, here at Bedrock, would like to thank you for joining.

Best wishes
Barney
</cfmail>
<cfoutput>
    <p>Thank you test for registering.
     We have just sent you an email.</p>
</cfoutput>

Answer 2

我以这种方式传递参数：

@Override
public synchronized boolean addPerson(Person person){
           if (personDAO.personExists(person.getFirstName(), person.getLocation())) {
               return false;
           } else {
               personDAO.addPerson(person);
               return true;
           }
}

并在控制器中

@RequestMapping(value= "/person", method = RequestMethod.POST)
public ResponseEntity<Void> addPerson(@RequestBody Person person, UriComponentsBuilder builder) {
    boolean flag = personService.addPerson(person);
           if (flag == false) {
          return new ResponseEntity<Void>(HttpStatus.CONFLICT);
           }
           HttpHeaders headers = new HttpHeaders();
           headers.setLocation(builder.path("/person/{id}").buildAndExpand(person.getPid()).toUri());
           return new ResponseEntity<Void>(headers, HttpStatus.CREATED);
}

Hibernate＆＃34; org.hibernate.QueryException＆＃34;

2 个答案: