Question

我想在表格中获得一列的总和。

tes.mat

它有错误：

org.hibernate.QueryException：无法解析属性：TransId：entities.PaymentLog [从entities.PaymentLog p中选择p，其中p.TransId如：TransId]

这是我的实体

public class PaymentLogDAO extends AbstractModel<PaymentLog> {
    public PaymentLogDAO() {
        super(PaymentLog.class);
    }
        public BigDecimal sum(String keyword) {
        try {
            if (!sessionFactory.getCurrentSession().getTransaction().isActive())
                sessionFactory.getCurrentSession().getTransaction().begin();    
            Query query = sessionFactory.getCurrentSession()
                    .createQuery("select sum(p.Payment) "
                            + "from PaymentLog p "
                            + "where p.TransId =:TransId");
            query.setParameter("TransID", keyword);
            return (BigDecimal) query.uniqueResult();
        } catch (Exception e) {
            System.out.println(e);
            return BigDecimal.valueOf(0);    
        }

    }
}

这是我的@Entity @Table(name="PaymentLog" ,schema="dbo" ,catalog="Project2" ) public class PaymentLog implements java.io.Serializable { private int id; private LoanLog loanLog; private Date transDate; private BigDecimal payment; public PaymentLog() { } public PaymentLog(int id) { this.id = id; } public PaymentLog(int id, LoanLog loanLog, Date transDate, BigDecimal payment) { this.id = id; this.loanLog = loanLog; this.transDate = transDate; this.payment = payment; } public PaymentLog(int id, LoanLog loanLog) { throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates. } @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "Id", unique = true, nullable = false) public int getId() { return this.id; } public void setId(int id) { this.id = id; } @ManyToOne(fetch=FetchType.LAZY) @JoinColumn(name="TransId") public LoanLog getLoanLog() { return this.loanLog; } public void setLoanLog(LoanLog loanLog) { this.loanLog = loanLog; } @Temporal(TemporalType.TIMESTAMP) @Column(name="TransDate", length=23) public Date getTransDate() { return this.transDate; } public void setTransDate(Date transDate) { this.transDate = transDate; } @Column(name="Payment", scale=4) public BigDecimal getPayment() { return this.payment; } public void setPayment(BigDecimal payment) { this.payment = payment; } }中的LoanLog实体TransId是PaymentLog中Id的外键

LoanLog

我该如何解决？非常感谢你

Answer 1

参考此URL（请参阅Select子句），字段必须是您拥有的实体的一部分。所以我猜你的选择必须引用Id字段而不是TransId（我也认为Id必须映射到TransId，因为名称不同） http://www.tutorialspoint.com/hibernate/hibernate_query_language.htm

Answer 2

你没有发布你的LoanLog实体，但我猜你的id属性为LoanLog或类似，所以试试这个

select sum(p.Payment) "
+ "from PaymentLog p "
+ "where p.loanLoag.id =:TransId

您在transId实体中引用了PaymentLog属性，该属性存在于java中。它存在于数据库中，但由于您没有执行本机查询，因此查询必须符合java规则，这意味着：在实体中查找属性并且transId属性不存在。

org.hibernate.QueryException：无法解析属性

2 个答案: