Question

this.createEmptyMovieClip("noise1",getNextHighestDepth());
noise1 = new Sound(noise1);
noise1.attachSound("noise1");
noise1.start(0,99999);
noise1.setVolume(0);

this.createEmptyMovieClip("noise2",getNextHighestDepth());
noise2 = new Sound(noise2);
noise2.attachSound("noise2");
noise2.start(0,99999);
noise2.setVolume(0);

this.createEmptyMovieClip("noise3",getNextHighestDepth());
noise3 = new Sound(noise3);
noise3.attachSound("noise3");
noise3.start(0,99999);
noise3.setVolume(0);

我如何将这些压缩成一个函数。一个看起来像这样的函数：

function soundclip(soundname){
    this.createEmptyMovieClip("soundname",getNextHighestDepth());
    soundname = new Sound(soundname);
    soundname.attachSound("soundname");
    soundname.start(0,99999);
    soundname.setVolume(0);

}

我希望soundname替换函数中的所有声音名称，包括引号中的声音名称。他们必须有相同的名字。我会调用这样的函数：

soundclip(noise1);
soundclip(noise2);
soundclip(noise3);

会产生上述内容。我的语法不好。我已经尝试了所有涉及在函数中使用引号的内容，或者根本没有，我尝试使用toString（）但没有成功。谢谢你的帮助

Answer 1

返回声音对象并将其指定给命名变量：

function soundclip(soundname){
    var mc = this.createEmptyMovieClip(soundname + "_mc",getNextHighestDepth());
    var sound = new Sound(mc);
    sound.attachSound(soundname);
    sound.start(0,99999);
    sound.setVolume(0);
    return sound;
}



noise1 = soundclip("noise1");
noise2 = soundclip("noise2");
noise3 = soundclip("noise3");

函数属性引用引号中的id

1 个答案: