Question

我已加载内容模块，我得到的具体错误是：The constructor Intent(new View.OnClickListener(){}, Class<ContactWidget>) is undefined

有关于此的任何想法吗？我从这里的教程中得到了这个：http://developer.android.com/guide/topics/ui/notifiers/notifications.html

package com.example.contactwidget;

import android.app.Activity;
import android.app.Notification;
import android.app.NotificationManager;
import android.app.PendingIntent;
import android.content.Context;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;

public class ContactWidget extends Activity {
    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        Button calc1 = (Button) findViewById(R.id.calc_button_1);
        calc1.setOnClickListener(buttonListener);

        setContentView(R.layout.main);
    }

    private static final int HELLO_ID = 1;

    private OnClickListener buttonListener = new OnClickListener() {
        public void onClick (View v) {
            String ns = Context.NOTIFICATION_SERVICE;
            NotificationManager mNotificationManager = (NotificationManager) getSystemService(ns);

            int icon = R.drawable.icon;
            CharSequence ticketBrief = "Button Pressed Brief";
            CharSequence ticketTitle = "Button pressed";
            CharSequence ticketText = "You pressed button 1";
            long when = System.currentTimeMillis();

            Notification notification = new Notification(icon, ticketBrief, when);

            Intent notificationIntent = new Intent(this, ContactWidget.class);
            PendingIntent contentIntent = PendingIntent.getActivity(this, 0, notificationIntent, 0);

            notification.setLatestEventInfo(getApplicationContext(), ticketTitle, ticketText, contentIntent);

            mNotificationManager.notify(HELLO_ID, notification);
        }
    };
}

Answer 1

改变这个：

new Intent(this, ContactWidget.class);

到

new Intent(ContactWidget.this, ContactWidget.class);

发生错误的原因是，在这种情况下，this引用OnClickListener的实例，但Intent's构造函数需要Context。您必须传递的上下文是对活动本身的引用，因此您必须使用ContactWidget.this显式访问它。

Answer 2

传入的上下文可能来自远程应用程序主机...显然，您需要来自应用程序的应用程序上下文，与您的类（例如您的广播接收器）的应用程序上下文。 Intent intent = new Intent（context.getApplicationContext（），WidgetryBroadcastReceiver.class）; 代替 Intent intent = new Intent（context，WidgetryBroadcastReceiver.class）; 去图。

Answer 3

是的，这对我来说也适用于

中的错误

Geocoder gc = new Geocoder(this, Locale.getDefault());

构造函数Intent未定义

3 个答案: