构造函数Intent是未定义的错误

时间:2013-03-26 02:16:49

标签: android android-intent android-fragments android-activity

我正在使用片段。我在片段中有一个微调器。我想在选择微调器项目时进行新的活动。我收到此错误

错误

构造函数Intent(UserHomeActivity,Class)未定义UserHomeActivity.java / SwipeyTabs / src / com / recscores / android line 28 Java问题

public class UserHomeActivity extends SherlockFragment{

Spinner spinnerTeam;
Spinner spinnerLeague;

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState){
    View view =inflater.inflate(R.layout.user_home, container, false);


    // Team Spinner
    spinnerTeam = (Spinner)view.findViewById(R.id.spinner_team);
    spinnerTeam.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
        public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) { 
            **Intent ii = new Intent(UserHomeActivity.this,TeamHomeActivity.class);
            startActivity(ii); **
        } 

        public void onNothingSelected(AdapterView<?> adapterView) {
            return;
        } 
    }); 

1 个答案:

答案 0 :(得分:10)

以...开始新活动:

Intent ii = new Intent(getActivity(),TeamHomeActivity.class);
 startActivity(ii); 

因为Context不是SherlockFragment类的超类,你需要使用getActivity()将当前片段的Activity返回关联。