我跟随this tutorial关注rails API,但它有点过时,有些东西似乎不适用于较新版本的rails。我很难用户控制器规格:
require 'rails_helper'
RSpec.describe Api::V1::UsersController, type: :controller do
describe "GET #show" do
before(:each) do
@user = FactoryGirl.create :user
get :show, params: {id: @user.id}
end
it "returns the information about a reporter on a hash" do
user_response = JSON.parse(response.body, symbolize_name: true)
expect(user_response[:email]).to eql @user.email
end
it { expect(response).to have_http_status(200) }
end
end
class Api::V1::UsersController < ApplicationController
def show
render json: User.find(params[:id])
end
end
FactoryGirl.define do
factory :user do
email { FFaker::Internet.email }
password "12345678"
password_confirmation "12345678"
end
end
但是,这不起作用,电子邮件似乎并不匹配。什么想法可能是错的?
故障:
1) Api::V1::UsersController GET #show returns the information about a reporter on a hash
Failure/Error: expect(user_response[:email]).to eql @user.email
expected: "mitzie_nikolaus@rice.com"
got: nil
(compared using eql?)
# ./spec/controllers/api/v1/users_controller_spec.rb:12:in `block (3 levels) in <top (required)>'
答案 0 :(得分:0)
代码是正确的,但您在使用symbolize_names
的{{1}}选项时输错了。
我认为,因为你没有复制粘贴示例,而是自己输入,这很好,因为它更适合学习。
要修正测试,只需更正此行(将JSON.parse
更改为symbolize_name
):
symbolize_names