Question

我试图在团结中读一个json时遇到了问题。我收到此消息“ArgumentException：JSON解析错误：无效的值。”。我的JSON看起来像：

[{"equipo":"Boca","pj":"5","pg":"3","pp":"2"}] and it is ok in unity.

这是我的信息类

[Serializable]
public class Response
{
    public string equipo;
    public int pj;
    public int pg;
    public int pp;
}

这是我在唤醒功能中调用的协程

IEnumerator RequestCorutine()
{
    var req = new WWW("http://localhost/test/item.php?team=Boca");
    yield return req;
    print(req.text);

    //var json = req.text;
    string json = System.Text.Encoding.UTF8.GetString(req.bytes, 3, 
    req.bytes.Length - 3);
    Response response = JsonUtility.FromJson<Response>(json);
    print("Equipo: " + response.equipo + " PJ: " + response.pj + " PG: " + 
    response.pg + " PP: " + response.pp);
}

我在此行中收到错误：Response response = JsonUtility.FromJson<Response>(json);

我为我的英语道歉，不是那么好。感谢。

Answer 1

[{"equipo":"Boca","pj":"5","pg":"3","pp":"2"}]

应该是

{"equipo":"Boca","pj":5,"pg":3,"pp":2}

因为方括号用于在json中声明数组。您声明的是List<Response>而不是单Response。另外，我删除了数字周围的引号。

问题与团结JsonUtility.FromJson

1 个答案: