我正在尝试编写一个脚本,该脚本读取具有名为ElementAbundance
的字段的特定hdf5文件,该字段具有化学元素的分数值。
这就是我正在做的事情,我打开hdf5文件,我列出了该文件中的字段。如果文件包含ElementAbundance
,则会检查field
中我要求的元素是否在elements
数组中。如果它在数组中,那么我想要将我要求的元素作为单个字符串返回。
我已经在其他地方查了过,ElementAbundance
中的字段是
elements = ['Carbon', 'Helium', 'Hydrogen', 'Iron', 'Magnesium', 'Neon', 'Nitrogen', 'Oxygen', 'Silicon']
import h5py
from particleType import partTypeNum # This is another file that is unimportant in regards to my question
# Only necessary if gas (0) particle type
def loadElement(basePath,snapNum,partType,field=None):
result = {}
# This uses the above module to associate keys words with the letter 0
ptNum = partTypeNum(partType)
gName = "PartType" + str(ptNum)
# making sure fields is not a single element
if isinstance(field, basestring):
field = [field]
# begin by opening the h5py file
with h5py.File(snapPath(basePath,snapNum),'r') as f:
# header = dict( f['Header'].attrs.items() )
# nPart = getNumPart(header)
# This creates a list for all the fields in the HDF5 file
field_list = []
for i in f[gName].keys():
field_list.append(str(i))
# This will check if the file has a "ElementAbundance" header
for i in enumerate(field_list):
# if the string is not inside the list, we raise an exception
if "ElementAbundance" not in field_list:
raise Exception("Particle type ["+str(ptNum)+"] does not have a field of elements")
# If it is, we extract the chemical elements from inside the element abundance field.
else:
g = f[gName]['ElementAbundance'] # file contains elements
elements = []
for j in g.keys():
elements.append(str(j))
# now for looping the lists values with their index
for i,element in enumerate(elements):
# if the element field is inside the elements list, we retrieve that element as a string
if field == element:
the_element = str(elements[i])
return the_element
# if their is a ElementAbundance field but the asked for field element is not in that list, raise and exception.
else:
raise Exception("Element type ["+str(field)+"] not found in element abundance list.")
f.close()
# testing to see if the above for loop returns a single string
return the_element
现在我测试一下,如果它返回字符串' Hydrogen',但是我返回了例外:Exception: Element type [['Hydrogen']] not found in element abundance list.
这很奇怪,因为Hydrogen
应该在我所做的elements
列表中。此外,引发的异常应该返回['Hydrogen']
而不是[['Hydrogen']]
。
如果他们是我可以添加的任何其他信息,请告诉我们!
答案 0 :(得分:1)
如果您将该功能称为:
loadElement(basePath,snapNum,partType,field='Hydrogen')
然后将'Hydrogen'变成单项目列表:
if isinstance(field, basestring):
field = [field]
当您迭代元素列表时,您正在迭代字符串并将它们与['Hydrogen']
匹配,这是一个列表,因此找不到匹配项。