Question

我必须开发一个符合某些逻辑的代码

这里

count（$ replylies） - 计算页面上的总回复

$ replynumber - 根据所做的回复总数，每个回复是1,2,3,4,5,6,7,8,9,10,11,12,13,14,15等。用户在帖子中

我试图根据回复显示基于adsense和其他广告脚本的自定义广告脚本

    <?php 

    if( count( $replies ) <= 3 )
                    {   
                     <script async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
<!-- ad-->
<ins class="google"
     style="display:inline-block;width:200px;height:90px"
     data-ad-client="ca-pub-xxxxx"
     data-ad-slot="xxxx"></ins>
<script>
(adsbygoogle = window.adsbygoogle || []).push({});
</script>
                }

else if(((count( $replies ) > 3) and (count( $replies ) <= 6)) and ($replynumber == '1','3','5'))
                {           
                 <script async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
<!-- ad2-->
<ins class="google"
     style="display:inline-block;width:200px;height:90px"
     data-ad-client="ca-pub-xxxxx"
     data-ad-slot="xxxx"></ins>
<script>
(adsbygoogle = window.adsbygoogle || []).push({});
</script>
                }

else if(((count( $replies ) > 6) and (count( $replies ) <= 12)) and ($replynumber == '1','4','7','10'))
                {           
                 <script async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
<!-- ad3-->
<ins class="google"
     style="display:inline-block;width:200px;height:90px"
     data-ad-client="ca-pub-xxxxx"
     data-ad-slot="xxxx"></ins>
<script>
(adsbygoogle = window.adsbygoogle || []).push({});
</script>               }               
               }
else if( count( $replies ) > 12 )
                {           
                 <script async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
<!-- ad4-->
<ins class="google"
     style="display:inline-block;width:200px;height:90px"
     data-ad-client="ca-pub-xxxxx"
     data-ad-slot="xxxx"></ins>
<script>
(adsbygoogle = window.adsbygoogle || []).push({});
</script>
                }                           
?>

但这会导致解析错误请任何人帮忙吗

Answer 1

是因为php可以解析de script标签。你需要像这样关闭de php吗？＆gt;在脚本之前，他们再次打开它或用回声打印它，例如：选项1：

if( count( $replies ) <= 3 )
{   
?>
 <script>       
 Script 1 to display
 </script>
<?php
}

选项2：

<?php 
if( count( $replies ) <= 3 )
   {   
    echo "  <script>       
    Script 1 to display
    </script>";
 }

如果php中的Statement导致解析错误

1 个答案: