Question

我有这个伪代码，我一直在尝试为和创建正确的PHP语法我绝对无处可去。我继续在函数group_job_items上得到一个Parse错误。

解析错误：语法错误，第17行意外“{”

这里有什么问题？任何帮助将不胜感激。

function group_job_items ()
{
    $jobs_by_category = array();
    foreach ($category_name as $category_id => $name)
    {
        foreach ($job_item as $item)
        {
            // skip job items that do not match the current category
            if ($item["category_id"] != $category_id) continue;

            if (!isset ($jobs_by_category[$name])
            {
                // create a list of jobs for the current category
                $jobs_by_category[$name] = array();
            }

            // add the current job item to the current category
            $jobs_by_category[$name][] = $item
        }
    }
}

Answer 1

<?php

function group_job_items ()
{
    $jobs_by_category = array();
    foreach ($category_name as $category_id => $name)
    {
        foreach ($job_item as $item)
        {
            // skip job items that do not match the current category
            if ($item["category_id"] != $category_id) continue;

            if (!isset ($jobs_by_category[$name]))
            {
                // create a list of jobs for the current category
                $jobs_by_category[$name] = array();
            }

            // add the current job item to the current category
            $jobs_by_category[$name][] = $item;
        }
    }
}
?>

Answer 2

更改...

if (!isset ($jobs_by_category[$name])
            {
                // create a list of jobs for the current category
                $jobs_by_category[$name] = array();
            }

到

if (!isset ($jobs_by_category[$name]))
            {
                // create a list of jobs for the current category
                $jobs_by_category[$name] = array();
            }

Answer 3

提交的代码中存在一些语法错误。

此行末尾缺少右括号/括号：

if (!isset ($jobs_by_category[$name])

这一行末尾缺少一个分号：

$jobs_by_category[$name][] = $item

进行这些更正应解决PHP解析器错误。

if语句中的PHP Parse语法错误

3 个答案: