Question

我有一个带有以下索引的pandas Dataframe：秒频率：

DatetimeIndex(['2015-12-28 05:20:05', '2015-12-28 05:20:06',
               '2015-12-28 05:20:07', '2015-12-28 05:20:08',
               ...
               '2015-12-28 21:19:55', '2015-12-28 21:19:56',
               '2015-12-28 21:19:57', '2015-12-28 21:19:58']

我想在给定日期时间字符串列表的情况下一次提取多行。我试过了：

df.loc[['2015-12-28 08:32:39', '2015-12-28 08:32:48']]

但是我收到以下错误：

KeyError: "None of [['2015-12-28 08:32:39', '2015-12-28 08:32:48']] are in the [index]"

Answer 1

您可以DatetimeIndex或to_datetime将list转换为datetime：

d = ['2015-12-28 05:20:05', '2015-12-28 21:19:58']
print (df.loc[pd.DatetimeIndex(d)])

或者：

print (df.loc[pd.to_datetime(d)])

样品：

idx = pd.DatetimeIndex(['2015-12-28 05:20:05', '2015-12-28 05:20:06',
               '2015-12-28 05:20:07', '2015-12-28 05:20:08',
               '2015-12-28 21:19:55', '2015-12-28 21:19:56',
               '2015-12-28 21:19:57', '2015-12-28 21:19:58'])
df = pd.DataFrame({'s': range(8)}, index=idx)  
print (df)
                     s
2015-12-28 05:20:05  0
2015-12-28 05:20:06  1
2015-12-28 05:20:07  2
2015-12-28 05:20:08  3
2015-12-28 21:19:55  4
2015-12-28 21:19:56  5
2015-12-28 21:19:57  6
2015-12-28 21:19:58  7

d = ['2015-12-28 05:20:05', '2015-12-28 21:19:58']
print (df.loc[pd.to_datetime(d)])
                     s
2015-12-28 05:20:05  0
2015-12-28 21:19:58  7

print (df.loc[pd.to_datetime(d)])
                     s
2015-12-28 05:20:05  0
2015-12-28 21:19:58  7

Pandas：使用DatetimeIndices列表从DataFrame中提取多行

1 个答案: