Question

我在游戏开始时播放了一个声音文件：

    // Play the start sound:
    self.run(SKAction.playSoundFileNamed("Sound/StartGame.aif", waitForCompletion: false))

如何从阵列中获取随机单个声音文件？

Answer 1

试试这个：

let soundNames = ["soundName1", "soundName2", "soundName3"]
let randomSoundName = soundNames[Int(arc4random_uniform(UInt32(soundNames.count)))]

let randomSound = self.run(SKAction.playSoundFileNamed(randomSoundName, waitForCompletion: false))

Answer 2

创建一个包含所有音乐文件名eg.Sound/StartGame.aif的数组，并在需要播放声音时随机选择一个。

Answer 3

首先，您必须在数组中添加所有声音名称，并从阵列中获取声音的随机名称。

let arrSound = ["Sound/StartGame.aif","Sound/StartGame2.aif"]

获取声音的随机名称。

let randomSound = arrSound[Int(arc4random_uniform(arrSound.count))]

self.run(SKAction.playSoundFileNamed(randomSound, waitForCompletion: false))

在Swift 3中播放数组中的随机声音

3 个答案: