Question

我创建了一个动态表。用户可以添加和删除行。在每一行中都有用于上传文件的列。

<tr><td><label><input type='file' class='upload_act' /></td></tr>

我使用function将name添加到文件上传中，因为表格行可能会频繁更改。

function reCalculate(){
    $("#t_object tbody .tr_content").each(function(i){
        $(this).find('td:eq(0)').text(i+1);
        $(this).find("input[class^='date_uploaded']").attr('name',"detail["+i+"][dt_upl]");
        $(this).find("input[class^='upload_act']").attr('name',"detail["+i+"][upload_act]");
    }); 
}

这是我处理提交的文件：

public function save_activity_m(){

    $details = $this->input->post('detail');
    $i       = 0;
    foreach($details as $rows){

        //UPLOAD RULES
        $upload_name             = "detail[".$i."][upload_act]";
        $config['upload_path']   = FCPATH."assets/uploads/memo/";
        $config['allowed_types'] = 'gif|jpg|jpeg|png|pdf|rar|zip|7z';
        $config['max_size']      = '2048';
        $config['file_name']     = $rows['dt_upl'];
        $config['remove_spaces'] = TRUE;        
        $config['overwrite']     = TRUE;

        $this->load->library('upload', $config);

        $this->upload->initialize($config);

        if(!$this->upload->do_upload($upload_name)){
            echo "<script type='application/javascript'>";
            echo "alert('Oops something wrong. Please contact the admin');window.top.location.reload();";
            echo "</script>";   
        }
        else{
            $i += 1;

            echo "<script type='text/javascript'>alert('Congratulaions. Your data is succesfully saved');window.top.location.reload();</script>";
        }
    }

    //echo json_encode($details);
}

我认为问题出在$upload_name。但是，我不知道什么是错的。我需要一些启发。

注意：
忽略IF，数据已成功保存，但文件未上传

如何在动态表上上传多个文件？

0 个答案: