protected void btnUpload_Click(object sender, EventArgs e)
{
for (int i = 0; i < Request.Files.Count; i++)
{
HttpPostedFile PostedFile = Request.Files[i];
if (PostedFile.ContentLength > 0)
{
string FileName = System.IO.Path.GetFileName(PostedFile.FileName);
PostedFile.SaveAs(Server.MapPath("Files\\") + FileName);
}
}
}
<script type="text/javascript">
var counter = 0;
function AddFileUpload() {
var div = document.createElement('DIV');
div.innerHTML = '<input id="file' + counter + '" name = "file' + counter +
'" type="file" />' +
'<input id="Button' + counter + '" type="button" ' +
'value="Remove" onclick = "RemoveFileUpload(this)" />';
document.getElementById("FileUploadContainer").appendChild(div);
counter++;
}
function RemoveFileUpload(div) {
document.getElementById("FileUploadContainer").removeChild(div.parentNode);
}
</script>
上传功能可以动态添加用户想要的内容。
<div>
<span style="font-family: Arial">Click to add files</span>
<input id="Button1" type="button" value="add" onclick="AddFileUpload()" />
<div id="FileUploadContainer">
</div>
<asp:Button ID="btnUpload" runat="server"
Text="Upload" OnClick="btnUpload_Click" />
</div>
我现在面临的问题是当我点击上传时
for (int i = 0; i < Request.Files.Count; i++)
这一行Request.Files.Count always = 0
,即使我有一个或多个要上传的文件。我也试图调试此Request.Files.Count 0
..
答案 0 :(得分:1)
只需将FileUploadContainer
div和Upload Button
包裹在form
中,并将其方法设置为POST
。现在您应该在Request.Files.Count
下获取文件。只是下面的一个示例
<div>
<span style="font-family: Arial">Click to add files</span>
<input id="Button1" type="button" value="add" onclick="AddFileUpload()" />
<form id="frmUploads" runat="server" method="POST">
<div id="FileUploadContainer">
</div>
<asp:Button ID="btnUpload" runat="server" Text="Upload" OnClick="btnUpload_Click" />
</form>
</div>
答案 1 :(得分:1)
运行您的页面,查看源代码并确保文件上传按钮和容器div包含在表单元素中,如果没有,则使用以下表单元素声明将它们包围起来
<form method='POST' enctype='multipart/form-data'>
<div>
<!-- REST of your HTML --!>
<span style="font-family: Arial">Click to add files</span>
<input id="Button1" type="button" value="add" onclick="AddFileUpload()" />
<div id="FileUploadContainer">
</div>
<asp:Button ID="btnUpload" runat="server"
Text="Upload" OnClick="btnUpload_Click" />
</div>
</form>