如何将文本与列表分开?

时间:2017-07-18 16:13:29

标签: python string list split charactercount

这是我的代码,但它一直在输出答案,而我希望它能够计算句子中的字符。

#-----------------------------
myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"
newSentence = Sentence.split(",")
myList.append(newSentence)
print(myList)
for character in myList:
    characterCount += 1
print (characterCount)

谢谢你的帮助

3 个答案:

答案 0 :(得分:0)

单行解决方案

len(list("hello world"))  # output 11

...或

快速修复原始代码

修订代码:

#-----------------------------
myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"
myList = list(Sentence)
print(myList)
for character in myList:
    characterCount += 1
print (characterCount)

输出:

['h', 'e', 'l', 'l', 'o', ' ', 'w', 'o', 'r', 'l', 'd']
11

答案 1 :(得分:0)

你可以循环句子并按字母计算字符:

#-----------------------------
myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"

for character in Sentence:
    characterCount += 1

print(characterCount)

答案 2 :(得分:0)

基本上你犯了一些错误:拆分分隔符应该是' '而不是',而不需要创建新列表,而是循环使用单词而不是字符。

代码应如下所示:

myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"
newSentence = Sentence.split(" ")

for words in newSentence:
    characterCount += len(words)

print (characterCount)