Question

我对此很新，我不知道如何解决这个问题。我有一个经销商然后它在一开始就询问将要玩多少玩家。然后每个玩家和经销商从一个牌组中分配2张牌。问题是，例如，如果我有3个玩家，代码也会列出下一个玩家的前两张牌。

Answer 1

你可能想要每个玩家一个列表。字典可能会完成这项工作，例如：

hands = {}
...
for player in players:
    hand = hands[player] = []
    for j in range(2):
         c = deck.pop()
         hand.append(c)


for player in players:
    print('{}: {}'.format(player, ', '.join(hands[player])))

Answer 2

您需要为每位玩家重置手牌。所以你的第二个循环看起来应该更像：

for i in range(players):
   hand = []
   for j in range(2):
      c = deck.pop()
      hand.append(c)
   print "Player " + str(i+1) + ":"
   print "Cards: " + cards.hand_display(cards)

否则hand将继续附加到。

Answer 3

你的手是一个单独的阵列，所以你只是将新卡附加到同一个阵列，每次你打印手，你打印相同的阵列，只有一开始它只有2张卡，然后4，那么6。

你应该做的是使用字典或数组数组。

Answer 4

import random

class Cards(object):
    suit  = ['H', 'D', 'S', 'C']
    value = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']

    def __init__(self):
        self.deck = [v+s for s in Cards.suit for v in Cards.value]

    def shuffle(self):
        random.shuffle(self.deck)

    def deal(self, n):
        res, self.deck = self.deck[:n], self.deck[n:]
        return res

show_hand = ' '.join

def main():
    num_players = 3
    deck = Cards()
    deck.shuffle()

    dealer  = deck.deal(2)
    players = [deck.deal(2) for i in xrange(num_players)]

    print('Hands:')
    print('  Dealer: {}'.format(show_hand(dealer)))
    for i in xrange(num_players):
        print('Player {}: {}'.format(i+1, show_hand(players[i])))

if __name__=="__main__":
    main()

结果

Hands:
  Dealer: JH 9H
Player 1: AS 2D
Player 2: QD 8H
Player 3: 10H 6D

Answer 5

您的代码（现已删除）的问题在于您将每个玩家手牌都附加到同一个列表中。简单的解决方法是在循环顶部重置变量。

由于您可能需要在玩游戏时跟踪所有牌局，因此创建一个单独的列表列表是有意义的，该列表包含经销商手牌的一个子列表，以及每个玩家的单独列表。这些可以存储在列表列表中，并根据需要编入索引。

你正在调用玩家：玩家1，玩家2等，实际上是从1开始编号，所以可以将经销商的牌存放在索引0中，并将玩家1的牌放在手中[玩家+1] ]，等等。这是一些示例代码：

#### testing scaffold #######################
import random

class Cards(object):
    def __init__(self):
        deck = self._deck = []
        for rank in "A23456789JQK":
            for suit in "CDHS":
                deck.append(rank+suit)

    def deck(self):
        return self._deck

    def hand_display(self, player_num):
        return ' '.join(hands[player_num])

cards = Cards()
players = 3
##########################################

deck = cards.deck()
random.shuffle(deck)
hands = [[]]  # for dealer's hand
hands.extend([] for player in range(players))  # for each player's hand
DEALER = 0
CARDS_PER_HAND = 2

print "Hands:"
for i in xrange (CARDS_PER_HAND):
    cd = deck.pop()
    hands[DEALER].append(cd)
print "Dealer: " + cards.hand_display(DEALER)

for player_num in [player+1 for player in range(players)]:
    for j in xrange(CARDS_PER_HAND):
        c = deck.pop()
        hands[player_num].append(c)
    print "Player " + str(player_num) + ":"
    print "Cards: " + cards.hand_display(player_num)

输出：

Hands:
Dealer: 6H 5H
Player 1:
Cards: 7H 3H
Player 2:
Cards: 4D JD
Player 3:
Cards: 3S 4S

如何分隔每个列表

5 个答案: