Question

是否可以简化这一点：

from tkinter import *
from random import randint


class BankAccount(object):
    def __init__(self, initial_balance=0):
        self.balance = initial_balance
    def deposit(self, amount):
        self.balance += amount
    def withdraw(self, amount):
        self.balance -= amount       
    def get_balance(self, initial_balance, rate):
        return self.get_balance() * self._rate

class BankAccountWithInterest(BankAccount):
    def __init__(self, initial_balance=0, rate=0.1):
        BankAccount.__init__(self, initial_balance)
        self._rate = rate           
    def interest(self):
        return self.balance * self._rate

balance = (randint(100, 500))
my_account = BankAccount(balance)
my_interest = BankAccountWithInterest(balance)
interest = my_interest.balance + my_interest.interest()

typeOfAccount = "1"
class GUI:
    def __init__(self, master):
        frame = Frame(master)
        frame.pack()


        #Toolbar#

        toolbar = Frame(root)
        toolbar.pack(side=TOP, fill=X)

        #Button#

        button1 = Button(toolbar, text="Deposit", width = 13,    command=self.depositBalance)
        button2 = Button(toolbar, text="Withdraw",width = 13, command=self.depositWithdraw)
        button1.pack(side=LEFT)
        button2.pack(side=RIGHT)

        #Menu#

        subMenu = Menu(menu)
        menu.add_cascade(label="Type of Account", menu=subMenu)
        subMenu.add_command(label="Standard", command= self.standard)
        subMenu.add_command(label="Interest", command= self.interest)

        #Textbox#

        self.text = Entry(root)
        self.text.pack()

        #Labels#

        w = Label(root, text="Current Balance:")
        w.pack()
        w1 = tkinter.StringVar()
        if typeOfAccount == "1":
            w1 = Label(root, text=my_account.balance)
            w1.pack()
        elif typeOfAccount == "2":
            w1.set(text=interest)
            w1.pack()


    def depositBalance(self):
            a = int(self.text.get())
            my_account.balance = a + my_account.balance
            print(my_account.balance)

    def depositWithdraw(self):
            a = int(self.text.get())
            my_account.balance = my_account.balance - a
            print(my_account.balance)         

    def standard(self):
        typeOfAccount = "1"

    def interest(self):
        typeOfAccount = "2"


root = Tk()
menu = Menu(root)
root.config(menu=menu)
root.title("Bank Account")
root.minsize(width=250, height=100)
root.maxsize(width=300, height=150)
GUI(root)

root.mainloop()

import numpy as np a = np.random.random_sample((40, 3)) data_base = np.random.random_sample((20, 3)) mean = np.random.random_sample((40,)) data = [] for s in data_base: data.append(mean + np.dot(a, s))应该是大小（20,40）。我想知道我是否可以做一些广播而不是循环。我无法使用data和一些np.add执行此操作。我当然不会正确使用它。

Answer 1

您的data创建了一个（20,40）数组：

In [385]: len(data)
Out[385]: 20
In [386]: data = np.array(data)
In [387]: data.shape
Out[387]: (20, 40)

dot的直接应用产生了同样的结果：

In [388]: M2=mean+np.dot(data_base, a.T)
In [389]: np.allclose(M2,data)
Out[389]: True

matmul运算符也适用于这些数组（无需展开和挤压）：

M3 = data_base@a.T + mean

在循环中简化numpy.dot

1 个答案: