Question

我有一个具有季度频率和3个时间变量的数据框， time 是一个字符变量。数据框如下所示

   dt <- structure(list(
  name1          =  c("C","C","C","C","C","C","B","B","B","B","B","B"),
  name2          =  c("D","E","A","D","E","A","D","E","A","D","E","A"),  
  year           =  c(2012, 2012, 2012, 2010, 2010, 2010, 2012, 2012, 2012, 2010, 2010, 2010 ),
  quarter        =  c(4,4,4,1,1,1,4,4,4,1,1,1),
  time           =  c("2012q4", "2012q4","2012q4","2010q1", "2010q1","2010q1","2012q4", "2012q4","2012q4","2010q1", "2010q1","2010q1")),
  .Names         =  c("name1","name2","year", "quarter", "time"),
  row.names      =  c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"), class =("data.frame"))

我想将 time 设置为我的时间序列变量，并按名称1（按字母顺序），名称2（按字母顺序）和时间（按时间顺序）对数据框进行排序。所需的输出应为

   dt <- structure(list(
 name1          =  c("B","B","B","B","B","B", "C","C","C","C","C","C"),
 name2          =  c("A", "A", "D", "D", "E", "E","A", "A", "D", "D", "E", "E"),  
 year           =  c(2010,2012,2010,2012,2010,2012,2010,2012,2010,2012,2010,2012),
 quarter        =  c(1,4,1,4,1,4,1,4,1,4,1,4),
 time           =  c("2010q1","2012q4", "2010q1","2012q4","2010q1","2012q4","2010q1","2012q4","2010q1","2012q4","2010q1","2012q4")),
 .Names         =  c("name1","name2","year", "quarter", "time"),
 row.names      =  c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"), class =("data.frame"))

我试过了。

 dt$time <- as.yearqtr(dt$time)
 dt <- dt[order(dt$name1, dt$name2, dt$time),]

提前致谢。

Answer 1

为什么使用$time而不是$year和$quarter？

只需dplyr::arrange(dt, name1, name2, year, quarter)。

使用季度频率从字符转换时间变量

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