Question

我有两个包含计划信息的表，我想要一个整合的多维数组。这是正确获取记录的函数。有些记录可能具有相同的内容。但它们会被＆＃39;类型＆＃39;进一步过滤。在其他地方见面：

function getAllScheduleItems($db){
  try {
    $schedule_items = array();
    $stmt = $db->prepare("(SELECT id, meeting_date, type, approved, expire_date FROM midweek_schedule)
      UNION (SELECT id, meeting_date, type, approved, expire_date FROM weekend_schedule)
      ORDER BY meeting_date ASC");

    if ($stmt->execute()) {
      while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
        $schedule_id = $row['id'];
        // So we have a news item.  Now add/create the read flag...
        $schedule_items[$schedule_id]['id'] = $schedule_id;
        $schedule_items[$schedule_id]['meeting_date'] = $row['meeting_date'];
        $schedule_items[$schedule_id]['type'] = $row['type'];
        $schedule_items[$schedule_id]['approved'] = $row['approved'];
        $schedule_items[$schedule_id]['expire_date'] = $row['expire_date'];
        echo "getAllScheduleItems- " . $row['meeting_date'] . "<br>";
      }
    }

    return $schedule_items;
  } catch(PDOException $ex) {
    logIt($db, "ERROR", "Database request for account information failed $ex");
    return 0;
  }
}

其他函数调用此结果以进一步过滤我的结果：

function getAllApprovedScheduleItems($db){
  $all_schedule_items = array();
  $all_schedule_items = getAllScheduleItems($db);
  $approved_schedule_items = array();

  foreach($all_schedule_items as $record){
    $schedule_id = $record['id'];
    if($record['approved'] == "Y"){
      $approved_schedule_items[$schedule_id]['id'] = $schedule_id;
      $approved_schedule_items[$schedule_id]['type'] = $record['type'];
      $approved_schedule_items[$schedule_id]['meeting_date'] = $record['meeting_date'];
      $approved_schedule_items[$schedule_id]['approved'] = $record['approved'];
      $approved_schedule_items[$schedule_id]['expire_date'] = $record['expire_date'];
      echo "getAllApprovedScheduleItems- " . $record['meeting_date'] . "<br>";
    }
  }
  return $approved_schedule_items;
}

最后是最后一次：

function getUnexpiredApprovedScheduleItems($db){
  $all_approved_schedule_items = array();
  $all_approved_schedule_items = getAllApprovedScheduleItems($db);
  $unexpired_approved_schedule_items = array();

  foreach($all_approved_schedule_items as $record){
    $schedule_id = $record['id'];
    $expire_date = $record['expire_date'];
    $stale_date = new DateTime($expire_date);
    $date1 = date("Y-m-d G:i:s");
    $now = new DateTime($date1);
    $interval = $now->diff($stale_date);
    if($stale_date >= $now){
      $unexpired_approved_schedule_items[$schedule_id]['id'] = $schedule_id;
      $unexpired_approved_schedule_items[$schedule_id]['meeting_date'] = $record['meeting_date'];
      $unexpired_approved_schedule_items[$schedule_id]['type'] = $record['type'];
      $unexpired_approved_schedule_items[$schedule_id]['expire_date'] = $record['expire_date'];
      $unexpired_approved_schedule_items[$schedule_id]['expire_days'] = $interval->days;
      echo "getUnexpiredApprovedScheduleItems- " . $record['meeting_date'] . "<br>";
    }
  }

正如您所看到的，我已经嵌入了回声语句，以了解发生了什么。带有单个字母的日期的最终打印输出来自刚刚从主php代码打印的最终php返回数组。我得到以下内容：

getAllScheduleItems- 1969-12-31
getAllScheduleItems- 1969-12-31
getAllScheduleItems- 1969-12-31
getAllScheduleItems- 2017-07-02
getAllScheduleItems- 2017-07-12
getAllScheduleItems- 2017-07-16
getAllScheduleItems- 2017-07-19
getAllScheduleItems- 2017-07-23
getAllScheduleItems- 2017-07-26
getAllScheduleItems- 2017-07-30
getAllScheduleItems- 2017-08-02
getAllScheduleItems- 2017-08-06
getAllApprovedScheduleItems- 2017-07-02
getAllApprovedScheduleItems- 2017-07-16
getAllApprovedScheduleItems- 2017-07-30
getAllApprovedScheduleItems- 2017-07-19
getAllApprovedScheduleItems- 2017-07-23
getAllApprovedScheduleItems- 2017-07-26
getAllApprovedScheduleItems- 2017-08-02
getAllApprovedScheduleItems- 2017-08-06
getUnexpiredApprovedScheduleItems- 2017-07-16
getUnexpiredApprovedScheduleItems- 2017-07-30
getUnexpiredApprovedScheduleItems- 2017-07-19
getUnexpiredApprovedScheduleItems- 2017-07-23
getUnexpiredApprovedScheduleItems- 2017-07-26
getUnexpiredApprovedScheduleItems- 2017-08-02
getUnexpiredApprovedScheduleItems- 2017-08-06
2017-07-16 W
2017-07-30 W
2017-07-19 M
2017-07-23 W
2017-07-26 M
2017-08-02 M
2017-08-06 W

为什么他们出了故障？我已经研究过多维排序，但我也想了解其中的原因。哦，如果我得到一个有效的多维排序的例子，那也很棒。

Answer 1

如果您有多个具有相同$schedule_id的记录，请执行以下操作：

$schedule_items[$schedule_id]['id'] = $schedule_id;

它不会在顶级$schedule_items数组中创建新元素，它只会覆盖数组中现有位置的$schedule_items[$schedule_id]元素。结果是数组不会按最终结果的日期排序，它将按照每个id的第一个项目的日期顺序排列。

如果您只想要每个id的第一个日期，您可以检查它是否已经在数组中，而不是添加替换：

  while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
    $schedule_id = $row['id'];
    if (isset($schedule_items[$schedule_id]))) {
        continue;
    }
    // So we have a news item.  Now add/create the read flag...
    $schedule_items[$schedule_id]['id'] = $schedule_id;
    $schedule_items[$schedule_id]['meeting_date'] = $row['meeting_date'];
    $schedule_items[$schedule_id]['type'] = $row['type'];
    $schedule_items[$schedule_id]['approved'] = $row['approved'];
    $schedule_items[$schedule_id]['expire_date'] = $row['expire_date'];
    echo "getAllScheduleItems- " . $row['meeting_date'] . "<br>";
  }
}

如果你想获得最后一个，你可以这样做：

unset($schedule_items[$schedule_id]);

在添加新项目之前。

您可能希望更改SQL查询，使其仅返回每个ID的第一行或最后一行，但由于UNION，这可能会变得复杂。

Answer 2

谢谢Barmar！我在考虑关联键。显然关键索引会覆盖！卫生署！我会给你正确答案，但我稍微修改了一下。我需要返回所有记录，所以我添加了一个简单的计数器来唯一标识每条记录。见下文

function getAllScheduleItems($db){
  try {
    $schedule_items = array();
    $stmt = $db->prepare("(SELECT id, meeting_date, type, approved, expire_date FROM midweek_schedule)
      UNION (SELECT id, meeting_date, type, approved, expire_date FROM weekend_schedule)
      ORDER BY meeting_date ASC");
    $schedule_id = 1; //Keep ALL record using a unique id
    if ($stmt->execute()) {
      while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
        //$schedule_id = $row['id'];
        // So we have a news item.  Now add/create the read flag...
        $schedule_items[$schedule_id]['id'] = $schedule_id;
        $schedule_items[$schedule_id]['meeting_date'] = $row['meeting_date'];
        $schedule_items[$schedule_id]['type'] = $row['type'];
        $schedule_items[$schedule_id]['approved'] = $row['approved'];
        $schedule_items[$schedule_id]['expire_date'] = $row['expire_date'];
        echo "getAllScheduleItems- " . $row['meeting_date'] . "<br>";
        $schedule_id++; //increment for each record returned
      }
    }

    return $schedule_items;
  } catch(PDOException $ex) {
    logIt($db, "ERROR", "Database request for account information failed $ex");
    return 0;
  }
}

PHP多维数组从MySQL查询中失序

2 个答案: