MySQL查询的多维数组

时间:2013-07-25 13:11:01

标签: php mysql arrays multidimensional-array

我正在尝试使用start_dateend_date值创建多维数组

$array = [];
$i = 0;

while ($row = mysqli_fetch_assoc($result)) {
    $array[$i]['start_date'] = $row['current_status_start_time'];
    $array[$i]['end_date'] = '';
    $i++;
}
print_r($array);

这会返回如下数组:

  Array ( 
    [0] => Array (
         [start_date] => 2013-07-25 11:18:42
         [end_date] => )
    [1] => Array (
         [start_date] => 2013-07-26 05:24:08
         [end_date] => )
    [2] => Array ( 
         [start_date] => 2013-07-31 17:25:05
         [end_date] => )
 ) 

end_date应该获得下一个数组[start_date]节点值:

        Array ( 
    [0] => Array (
         [start_date] => 2013-07-25 11:18:42
         [end_date] =>   **2013-07-26 05:24:08**)
    [1] => Array (
         [start_date] => **2013-07-26 05:24:08**
         [end_date] =>   2013-07-31 17:25:05)
    [2] => Array ( 
         [start_date] => 2013-07-31 17:25:05
         [end_date] => current_date)
 ) 

正如您在上一个代码示例中所看到的,array[0][end_date]应该获得array[1][start_date]值,依此类推,最后一个数组end_date应该获取当前时间值,因为数组已经结束

我应该使用第二个循环来实现吗?还是有其他更简单的方法?

2 个答案:

答案 0 :(得分:2)

这可以让你得到你想要的东西:

$array = [];
$i = 0;

while ($row = mysqli_fetch_assoc($result)) {
    $array[$i]['start_date'] = $row['current_status_start_time'];
    $array[$i]['end_date'] = '';
    if ($i > 0){
        // if we are pass the first item set the previous item to the current start date
        $array[$i-1]["end_date"] = $array[$i]['start_date'];
    }
    $i++;
}
// fill in the last end_date with the current_date
$array[$i]["end_date"] = date("Y-m-d H:i:s");
print_r($array);

答案 1 :(得分:1)

我会循环。像这样:

foreach($mainArray as $key => $value)
{
    $next = $key + 1;

    if(!is_null($mainArray[$next]['start_date']))
    {
        $mainArray[$key]['end_date'] = $mainArray[$next]['start_date'];
    }
    else
    {
        $mainArray[$key]['end_date'] = current_date;
    }
}

print_r($main_array);