Question

前几天我正在做一个javascript练习并且结束了一个奇怪的行为。如果你能解释一下，我将不胜感激。所以我们的目标是创建一个小脚本，创建一个单词中所有可能的后续字母组合。

例如。＆＃34;狗＆＃34; ＆GT;＆GT;＆GT; [＆＃34; d＆＃34;，＆＃34;做＆＃34;，＆＃34;狗＆＃34;，＆＃34; o＆＃34;，＆＃34; og＆＃34;，＆＃34;克＆＃34;];

function combCheck(w){
var arrayBase = [];
for (var i=0, y=1 ; y<=w.length; y++){
    arrayBase.push(w.slice(i,y));
    console.log("i is equal to: "+i);
    console.log("y is equal to: "+y);
    if (y==w.length) {
        i++;
        y = i;
        console.log("i in if part is equal to: " + i);
        console.log("y in if part is equal to: " + y);
    }
}
return arrayBase;

}

所以一切都运行得很酷，但有些东西我无法弄清楚。

    combCheck("dog");
VM720:5 i is equal to: 0
VM720:6 y is equal to: 1
VM720:5 i is equal to: 0
VM720:6 y is equal to: 2
VM720:5 i is equal to: 0
VM720:6 y is equal to: 3
VM720:10 i in if part is equal to: 1
VM720:11 y in if part is equal to: 1
VM720:5 i is equal to: 1
VM720:6 y is equal to: 2
VM720:5 i is equal to: 1
VM720:6 y is equal to: 3
VM720:10 i in if part is equal to: 2
VM720:11 y in if part is equal to: 2
VM720:5 i is equal to: 2
VM720:6 y is equal to: 3
VM720:10 i in if part is equal to: 3
VM720:11 y in if part is equal to: 3

你可以在日志行中看到：10解释器输入if语句并增加＆＃34; i＆＃34;按1并设置＆＃34; y＆＃34;达到＆＃34; i＆＃34;的价值因此，当解释器返回循环时，它们都具有1 但的值。＆＃34; y＆＃34;再次增加1。因为＆＃34; y＆＃34;不应该通过循环增加，我无论如何都无法解释它。我的意思是我们不应该将y设置为＆＃34; i + 1＆＃34;在脚本中？哪个更有意义？

提前致谢。

Answer 1

您的行为并非异常。在for循环中，变量的迭代位于尾部。您可以考虑执行代码，然后通过向y添加1来结束。

如果您希望迭代在开头，那么您可以使用while循环，并使循环中的第一个语句为y++。

对于循环奇怪的行为

1 个答案: