Question

在我的urls.py我已将handler404设为CustomErrorView。 CustomErrorView是一个通用视图，它根据错误消息和错误代码生成错误模板。

由于handler404仅在出现404错误的情况下被提出，因此如果errorcode = 404 kwarg被提升，我怎样才能将CustomErrorView kwarg发送给handler404 = CustomErrorView(errorcode = 404)？

已经尝试过 -

handler404 = CustomErrorView(request, errorcode = 404)
这导致＆＃34;预期的一个位置参数，没有给出错误。＆＃34;
Name 'request' is not defined
这会导致NameError（from django.conf.urls import url, include from django.contrib import admin from blog_user.views import home, create_error_view urlpatterns = [ url(r'^admin/', admin.site.urls), url(r'^$', home), url(r'^', include('user_manager.urls')), ] handler404 = create_error_view(error = 404) handler500 = create_error_view(error = 500)）

我的urls.py:

from django.shortcuts import render
from django.http import HttpResponse, HttpResponseNotFound

def create_error_view(error = 404, mybad = False):
    def custom_error_view(request, error, mybad):
        ''' Returns a generic error page. Not completed yet. error code and messages are supposed to be modular so that it can be used anywhere for any error in the page.'''
        content = "Incorrect url"
        context= {
            'error': error,
            'content':content,
            'mybad':mybad
        }
        response = render(request, 'error.html', context=context, status=error)
        return HttpResponse(response)
    return custom_error_view

我的views.py（使用@knbk推荐的修改后）：

using (StreamReader sr = new StreamReader(@"D:\Templates\NewGridTemplate.txt"))
            {
                // Read the stream to a string, and write the string to the console.
                obj.sGridTemplate = sr.ReadToEnd().Replace(Environment.NewLine, " ");
                //Console.WriteLine(line);
            }


            return View(obj);

Answer 1

您可以使用函数闭包来创建视图函数：

def create_error_view(error_code):
    def custom_error_view(request, *args, **kwargs):
        # You can access error_code here
    return custom_error_view

然后只需调用create_error_view来设置处理程序：

handler404 = create_error_view(error_code=404)

或者你可以使用functools.partial()，基本上也是这样：

from functools import partial

handler404 = partial(custom_error_view, error_code=404)

将参数传递给Django中的视图

1 个答案: