从Django视图传递参数以形成不起作用

时间:2018-04-25 05:51:58

标签: django django-models django-forms django-templates django-views

我一直在尝试将参数从我的createview传递给form,但是在表单中没有收到该参数。我不知道出了什么问题。

以下是我的观点,

class ItemCreateView(LoginRequiredMixin,CreateView):
   form_class       = ItemForm
   template_name    = 'form.html'

   def get_form_kwargs(self):
       kwargs = super(ItemCreateView, self).get_form_kwargs()
       kwargs['user'] = self.request.user # pass the 'user' in kwargs
       return kwargs 

   def get_context_data(self,**kwargs):
       context = super(ItemCreateView,self).get_context_data(**kwargs)
       context['title'] = 'Add Items'
       return context

   def form_valid(self,form):
       instance = form.save(commit = False)
       instance.user = self.request.user
       instance.save()
       return super(ItemCreateView, self).form_valid(form)

以下是我的表单类:

from django import forms
from .models import Item
from restaurants.models import RestaurantLocation

class ItemForm(forms.ModelForm):
    class Meta:
        model = Item
        fields=[
        'name',
        'restaurant',
        'contents',
        'excludes',
        'public'
        ]

    def __init__(self, *args, **kwargs): 
        user = kwargs.pop('user', None)
        print(user)
        super(ItemForm,self).__init__(*args,**kwargs)
        self.fields['restaurant'].queryset = RestaurantLocation.objects.filter(owner=user)

0 个答案:

没有答案