有人可以帮我解决SQL查询吗?我有一张表有这样的数据
Periodtable :
ID
StartDate
EndDate
数据如下所示:
1 1/3/2017 2/2/2017
2 2/3/2017 3/2/2017
3 3/3/2017 4/2/207
4 4/3/2017 5/2/2017
5 5/3/2017 6/2/2017
6 6/3/2017 7/2/2017
7 7/3/2017 8/2/2017
8 8/3/2017 9/2/2017
9 9/3/2017 10/2/2017
...
我想编写一个返回以下3列的SQL查询:
9,8,7 | 7/3/2017 | 10/2/2017
6,5,4 | 4/3/2017 | 7/2/2017
3,2,1 | 1/3/2017 | 4/2/2017
答案 0 :(得分:1)
下面的SQL使用xml路径技巧将Id折叠成一个列表,按季度分组
select
stuff(
(select concat(',',tid.ID)
from PeriodTable tid
where datepart(quarter,tid.Startdate) = datepart(quarter,t.Startdate)
and datepart(year,tid.Startdate) = datepart(year,t.Startdate)
for xml path(''), type).value('.', 'varchar(max)')
,1,1,'') IdList,
min(StartDate) as FirstStartDate, max(EndDate) as LastEndDate
from PeriodTable t
group by datepart(year,Startdate), datepart(quarter,Startdate)
order by FirstStartDate;
或者使用CROSS APPLY的方法的这种变化:
select
stuff(max(Ids),1,1,'') as IdList, min(StartDate) as FirstStartDate, max(EndDate) as LastEndDate
from PeriodTable t
cross apply (
select concat(',',tid.ID)
from PeriodTable tid
where datepart(quarter,tid.Startdate) = datepart(quarter,t.Startdate)
and datepart(year,tid.Startdate) = datepart(year,t.Startdate)
for xml path('')) List(Ids)
group by datepart(year,Startdate), datepart(quarter,Startdate)
order by FirstStartDate;