Question

transaction_date采用日期格式我实际上要输出的是按季度计算的唯一ID的DUNTINCT（即，给定四分之一的Unique_Id出现了多少次）。

SELECT  transaction_date ,
    UNIQUE_ID,
FROM    panel
     WHERE (some criteria = 'x') 
GROUP BY UNIQUE_ID

Answer 1

试试这个：

SELECT  datepart(quarter,transaction_date),
count(distinct UNIQUE_ID) as cnt
FROM    panel
WHERE (some criteria = 'x') 
GROUP BY datepart(quarter,p.transaction_date)

但是计数（不同）将进行排序，因此需要花费大量时间。所以你可以先在表格中区分它然后进行计数

SELECT  datepart(quarter,p.transaction_date),
count(p.UNIQUE_ID) as cnt
FROM   (select distinct transaction_date as transaction_date, UNIQUE_ID
        from panel) as p
WHERE (some criteria = 'x') 
GROUP BY datepart(quarter,p.transaction_date)

Answer 2

我会使用date_trunc：

select
  date_trunc ('quarter', transaction_date), count (distinct unique_id)
from panel
where criteria = 'x'
group by 1

这预示着当你说“按季度”时，2015年第1季度与2014年第1季度不同。

Answer 3

SELECT DATEPART(QUARTER, transaction_date) ,
COUNT(DISTINCT UNIQUE_ID),
FROM panel
GROUP BY transaction_date

SQL Group By季度日期

3 个答案: