我通过ajax获得了低于结果的结果,而我在ajax成功中得到的数据是
[{
"plants_ref_id": "1",
"plant_name": "MCW",
"employees_data": "6,6,80,70,60,30,2,3,12,12,37.00,60.00,64666.666667,8000.0000"
},{
"plants_ref_id": "3",
"plant_name": "SJCPL",
"employees_data": "4,5,6,7,7,7,6,4,4,5,20.00,3.00,176923.076923,38461.5385"
}]
我正在尝试将此数据转换为格式
[{
name: 'MCW',
data: [6,6,80,70,60,30,2,3,12,12,37.00,60.00,64666.666667,8000.0000
]},{
name: 'SJCPL',
data: [4,5,6,7,7,7,6,4,4,5,20.00,3.00,176923.076923,38461.5385]
}]
我正在尝试将此格式转换为https://jsfiddle.net/mcj075jf/
生成高级图表如何使用for循环或$.each
在jQuery中转换为上述格式。请帮忙。
答案 0 :(得分:1)
您可以按如下方式使用map
:
var plants = [{
"plants_ref_id": "1",
"plant_name": "MCW",
"employees_data": "6,6,80,70,60,30,2,3,12,12,37.00,60.00,64666.666667,8000.0000"
},{
"plants_ref_id": "3",
"plant_name": "SJCPL",
"employees_data": "4,5,6,7,7,7,6,4,4,5,20.00,3.00,176923.076923,38461.5385"
}];
var formattedData = plants.map((plant) => ({
name: plant.plant_name,
data: plant.employees_data.split(',').map((data) => parseFloat(data))
}));
console.log(formattedData);

答案 1 :(得分:0)
您可以使用解决方案https://jsfiddle.net/z10jheo2/
var data = [{
"plants_ref_id": "1",
"plant_name": "MCW",
"employees_data": "6,6,80,70,60,30,2,3,12,12,37.00,60.00,64666.666667,8000.0000"
},{
"plants_ref_id": "3",
"plant_name": "SJCPL",
"employees_data": "4,5,6,7,7,7,6,4,4,5,20.00,3.00,176923.076923,38461.5385"
}];
var newData = [];
for(var i=0; i<data.length; i++) {
var tempData = {};
tempData.name = data[i].plant_name;
tempData.data = data[i].employees_data.split(',');
newData.push(tempData);
console.log(newData);
}