我有一个json数据,它将根据用户选中的复选框从数据库中检索所选数据。但我知道我的json数据不正确。尝试了很多方式,但仍然不会工作。这是代码:
<?php
foreach ($_GET['iddoc'] as $iddoc) //iddoc is the value of checked checkbox
{
$query="select * from compareresult where iddocument=$iddoc";
$sql_query = mysql_query($query) or die('Error 3 :'.mysql_error());
while ($r = mysql_fetch_assoc($sql_query))
{
$series1['name'][] = $r['subject'];
$series1['data'][] = $r['result'];
}
$jsonTable = json_encode($series1, JSON_NUMERIC_CHECK);
echo $jsonTable;
}
根据下面的代码,假设我选中3复选框(BAT123,BIO222,HIS TEST),json输出将是这样的:
{"name":["BAT123"],"data":[3.03]}
{"name":["BAT123","BIO222"],"data":[3.03,1.05]}
{"name":["BAT123","BIO222","his test"],"data":[3.03,1.05,3.03]}
我知道上面的json是错误的,那么如何使json数据显示如下:
[
{"name":["BAT123"],"data":[3.03]},
{"name":["BIO222"],"data":[1.05]},
{"name":["his test"],"data":[3.03]}
]
这是我的highcharts javascript代码:
<script type="text/javascript">
$(function () {
var data = [
<?php echo $jsonTable; ?>
];
$(document).ready(function() {
chart = new Highcharts.Chart({
chart: {
renderTo: 'SamHistogramDiv',
type: 'column',
marginRight: 130,
marginBottom: 25
},
title: {
text: 'SAM Histogram Results',
x: -20 //center
},
subtitle: {
text: '',
x: -20
},
xAxis: {
categories: []
},
yAxis: {
title: {
text: 'Percentage'
},
plotLines: [{
value: 0,
width: 1,
color: '#808080'
}]
},
tooltip: {
formatter: function() {
return '<b>'+ this.series.name +'</b><br/>'+
this.x +': '+ this.y;
}
},
legend: {
layout: 'vertical',
align: 'right',
verticalAlign: 'top',
x: -10,
y: 100,
borderWidth: 0
},
series: data[0]
});
});
});
非常感谢你的时间..
答案 0 :(得分:0)
试试这个
foreach ($_GET['iddoc'] as $iddoc) //iddoc is the value of checked checkbox
{
$query="select * from compareresult where iddocument=$iddoc";
$sql_query = mysql_query($query) or die('Error 3 :'.mysql_error());
while ($r = mysql_fetch_assoc($sql_query))
{
$series[] = array('name'=>$r['subject'],'data'=>$r['result']);
}
}
$jsonTable = json_encode($series);
echo $jsonTable;
输出将像
[{"name":"BAT123","data":"3.03"},{"name":"BIO222","data":"1.05"},{"name":"HIs test","data":"1.00"}]
答案 1 :(得分:0)
问题在于json数据格式。它应该像
var data = [{name:"BAT123",data:[3.03]},{name:"BIO222",data:[1.05]},{name:"his test",data:[3.03]}];
foreach ($_GET['iddoc'] as $iddoc) //iddoc is the value of checked checkbox
{
$query="select * from compareresult where iddocument=$iddoc";
$sql_query = mysql_query($query) or die('Error 3 :'.mysql_error());
while ($r = mysql_fetch_assoc($sql_query))
{
$series[] = array('name'=>$r['subject'],'data'=>array($r['result']));
}
}
$jsonTable = json_encode($series);
echo $jsonTable;
请检查您是否获得了上面提到的json字符串/ * data * /