Question

我正在尝试编写一个代码，用于在vhdl

中乘以两个100x100矩阵

    library IEEE;
    use IEEE.STD_LOGIC_1164.ALL;
    use ieee.numeric_std.all;
    library work;
    use work.mult_100x100_pack.all;


    entity multiplier_main_code is
        Port ( in_matrix1 : in  t_2d_array;
               in_matrix2 : in  t_2d_array;
               out_matrix : inout  t_2d_array);
    end multiplier_main_code;

    architecture Behavioral of multiplier_main_code is

    begin

        process(in_matrix1, in_matrix2)
        begin
             for i in 0 to 99 loop
                  for j in 0 to 99 loop
                      for k in 0 to 99 loop
                       out_matrix(i)(j) <= std_logic_vector(signed(out_matrix(i)(j)) + (signed(in_matrix1(i)(k)) * signed(in_matrix2(k)(j))));

                      end loop;
                 end loop;
          end loop;          

    end Behavioral;

一次又一次地显示错误说：期待“行为”的类型无效
“行为”附近的语法错误

mult_100X100_pack包的代码是：

library IEEE;
use IEEE.STD_LOGIC_1164.all;
use ieee.numeric_std.all;

package mult_100x100_pack is

    type t_1d_array is array(integer range 0 to 99)of std_logic_vector(7 downto 0);
    type t_2d_array is array(integer range 0 to 99)of t_1d_array;


end mult_100x100_pack;

拜托，有人可以帮我解决这个错误吗？

Answer 1

修正缩进后，你应该很清楚你错过了什么：

process(in_matrix1, in_matrix2)
begin
  for i in 0 to 99 loop
    for j in 0 to 99 loop
      for k in 0 to 99 loop
        -- Do things
      end loop;
    end loop;
  end loop;
-- Perhaps `end process;` might be appropriate here...

Answer 2

您的<button id="Button">Generate a new div</button> <div id="Frame"></div>需要process：

end process;

这说明了注意正确缩进代码的优点。如果您的所有end loop; end process; end Behavioral;都与其对应的end for对齐，那么这一点就很明显了。

行为附近的语法错误

2 个答案: