Question

由zlib解压缩并打印到日志的字符串格式如下。

 {\x22uid\x22:\x22CE57134D17B57E873D7E7434E0E21783\x22.............2\x5Cu0000\x5Cu0000\x22,\x22http://tgs.7477.com/adiframe/ky/01/index.html\x5Cu0000\x5Cu0000\x22,\x22http://s.csbew.com/acookie.html\x5Cu0000\x5Cu0000\x22],\x22ver\x22:\x221\x22}\x0A200

如何对解压缩的str进行编码，使其显示时不会显示＆＃39; \ xxx \ u000＆＃39;在lua？

Answer 1

尝试使用此unescape函数从十六进制表示中获取字符：

    function unescape (s)
        s = string.gsub(s or '', "\\x(%x%x)", function (h) return string.char(tonumber(h,16)) end)
        return s
    end


    local str = [[{\x22uid\x22:\x22CE57134D17B57E873D7E7434E0E21783\x22.............2\x5Cu0000\x5Cu0000\x22,\x22http://tgs.7477.com/adiframe/ky/01/index.html\x5Cu0000\x5Cu0000\x22,\x22http://s.csbew.com/acookie.html\x5Cu0000\x5Cu0000\x22],\x22ver\x22:\x221\x22}\x0A200 ]]
    print( unescape(str) )

结果：

 {"uid":"CE57134D17B57E873D7E7434E0E21783".............2\u0000\u0000","http://tgs.7477.com/adiframe/ky/01/index.html\u0000\u0000","http://s.csbew.com/acookie.html\u0000\u0000"],"ver":"1"}
200

如何在lua中将字节编码为utf8？

1 个答案: