测试在Jasmine中具有构造函数方法的Angular2管道

时间:2017-07-04 16:30:09

标签: angular unit-testing typescript jasmine karma-jasmine

我正在测试一个有构造函数的Angular Pipe的第一个障碍。

我的管道如下:

reverse.pipe.ts

import {
  IterableDiffer,
  IterableDiffers,
  Pipe,
  PipeTransform
} from '@angular/core';

@Pipe({
  name: 'reverse',
  pure: false
})
export class ReversePipe implements PipeTransform {

  private cached: Array<any>;
  private differ: IterableDiffer<Array<any>>;

  constructor(private differs: IterableDiffers) {
    this.differ = this.differs.find([]).create(null);
  }

  transform(array: Array<any>): Array<any> {
    // TODO: Throw an error if `array` isn't an Array
    if (Array.isArray(array) === false) return [];

    const changes = this.differ.diff(array);

    if (changes) this.cached = array.slice().reverse();

    return this.cached;
  }
}

我相信通过几个教程,使用IterableDiffer来提高效率是正确的。但这不是这个问题的主题。

需要构造函数的事实,我相信这个简单测试失败的根源是:

reverse.pipe.spec.ts

import { ReversePipe } from './reverse.pipe';

describe('ReversePipe', () => {
  it('create an instance', () => {
    const pipe = new ReversePipe();
    expect(pipe).toBeTruthy();
  });
});

测试失败,错误为:TypeError: Cannot read property 'find' of undefined

这个(可能是错误的)假设是因为differs需要在测试中注入,因为错误消息表明它是undefined

我是否正确行,我应该如何为管道编写一个简单的测试?

更新

我试图将IterableDiffers注入正在测试的管道中;虽然这已经纠正了上一个错误,但我没有面对新的Error: Can't resolve all parameters for IterableDiffers: (?).

在终端中,显示错误Cannot invoke an expression whose type lacks a call signature. Type 'IterableDiffers' has no compatible call signatures.

两者都用不同的语言描述同样的问题。

我的更新测试是:

reverse.pipe.spec.ts

import { IterableDiffer, IterableDiffers } from '@angular/core';
import { TestBed, inject } from '@angular/core/testing';

import { ReversePipe } from './reverse.pipe';

describe('ReversePipe', () => {
  beforeEach(() => {
    TestBed.configureTestingModule({
      providers: [IterableDiffers]
    });
  });

  // it('create an instance', () => {
  //   const array = [ 1, 2, 3 ];
  //   const pipe = new ReversePipe(new IterableDiffers);
  //   expect(pipe).toBeTruthy();
  // });

  it('create an instance', inject([IterableDiffers], (iterableDiffers: IterableDiffers) => {
    const array = [ 1, 2, 3 ];
    const pipe = new ReversePipe(iterableDiffers);

    expect(pipe).toBeTruthy();
  }));
});

非常感谢任何和所有帮助。

1 个答案:

答案 0 :(得分:3)

我几乎在那里进行了更新的测试。您无需提供IterableDiffers

reverse.pipe.spec.ts

import { IterableDiffers } from '@angular/core';
import { TestBed, inject } from '@angular/core/testing';

import { ReversePipe } from './reverse.pipe';

describe('ReversePipe', () => {
  it('should create an instance', inject([ IterableDiffers ], (iterableDiffers: IterableDiffers) => {
    const pipe = new ReversePipe(iterableDiffers);

    expect(pipe).toBeTruthy();
  }));

  it('should reverse the array of type Array<number>', inject([ IterableDiffers ], (iterableDiffers: IterableDiffers) => {
    const array = [ 1, 2, 3 ];
    const pipe = new ReversePipe(iterableDiffers);

    expect(pipe.transform(array)).toEqual([ 3, 2, 1 ]);
  }));

  it('should reverse the array of type Array<string>', inject([ IterableDiffers ], (iterableDiffers: IterableDiffers) => {
    const array = [ 'apple', 'banana', 'clementine' ];
    const pipe = new ReversePipe(iterableDiffers);

    expect(pipe.transform(array)).toEqual([ 'clementine', 'banana', 'apple' ]);
  }));
});

我还注意到if中有一个不必要的reverse.pipe.spec.ts语句:

// TODO: Throw an error if `array` isn't an Array
if (Array.isArray(array) === false) return [];

transform的第一个参数始终是Array;当然,如果参数不是TypeError,那么TypeScript编译器会抛出Array

为了完整性,我的管道是:

reverse.pipe.ts

import {
  IterableDiffer,
  IterableDiffers,
  Pipe,
  PipeTransform
} from '@angular/core';

@Pipe({
  name: 'reverse',
  pure: false
})
export class ReversePipe implements PipeTransform {

  private cached: Array<any>;
  private differ: IterableDiffer<Array<any>>;

  constructor(private differs: IterableDiffers) {
    this.differ = this.differs.find([]).create(null);
  }

  public transform(array: Array<any>): Array<any> {
    const changes = this.differ.diff(array);

    if (changes) this.cached = array.slice().reverse();

    return this.cached;
  }
}